Answer:
x = 10
Step-by-step explanation:
Consecutive angles in a parallelogram are supplementary, thus
∠ A + ∠ B = 180, substitute values
9x + 8 + 8x + 2 = 180, that is
17x + 10 = 180 ( subtract 10 from both sides )
17x = 170 ( divide both sides by 17 )
x = 10
 
        
                    
             
        
        
        
You would assume that in this figure, the number of colored sections with which are not colored with respect to a " touching " colored section, would be half of the total colored sections. However that is not the case, the sections are not alternating as they still meet at a common point. After all, it notes no two touching sections, not adjacent sections. Their is no equation to calculate this requirement with respect to the total number of sections.
Let's say that we take one triangle as the starting. This triangle will be the start of a chain of other triangles that have no two touching sections, specifically 7 triangles. If a square were to be this starting shape, there are 5 shapes that have no touching sections, 3 being a square, the other two triangles. This is presumably a lower value as a square occupies two times as much space, but it also depends on the positioning. Therefore, the least number of colored sections you can color in the sections meeting the given requirement, is 5 sections for this first figure. 
Respectively the solution for this second figure is 5 sections as well.
 
        
             
        
        
        
Answer:

Step-by-step explanation:
For this case we have the following value:

We can convert this first to  like this:
 like this:

Now we use the fact the the pressure is defined as  , whre P is the pressure, F the force and A the area, so then
, whre P is the pressure, F the force and A the area, so then  and then we can replace this:
 and then we can replace this:

Now from definition of work we know that  where W is the work, F the force and d the distance, so then is equivalent
 where W is the work, F the force and d the distance, so then is equivalent 
And if we replace this into the equation we got:
