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2 years ago

I need to simplify for the question

Mathematics

2 answers:

Afina-wow [57]2 years ago

7 0

Answer:

$x^2 + 3xy + 4y^2$

Step-by-step explanation:

$(x - 2y)^2 + 7xy =$

$= (x - 2y)(x - 2y) + 7xy$

$= x^2 -2xy - 2xy + 4y^2 + 7xy$

$= x^2 + 3xy + 4y^2$

Anastaziya [24]2 years ago

6 0

Answer:

$\tt x^2+3xy+4y^2$

Step-by-step explanation:

$\tt(x-2y)^2+7xy\\\\=x^2-4xy+4y^2+7xy\\\\=x^2+3xy+4y^2$

You might be interested in

A supplier delivers an order for 20 electric toothbrushes to a store. By accident, three of the electric toothbrushes are defect

krek1111 [17]

Answer:

The probability that the first two electric toothbrushes sold are defective is 0.016.

Step-by-step explanation:

The probability of an event, say E occurring is:

$P (E)=\frac{n(E)}{N}$

Here,

n (E) = favorable outcomes

N = total number of outcomes

Let X = number of defective electric toothbrushes sold.

The number of electric toothbrushes that were delivered to a store is, n = 20.

Number of defective electric toothbrushes is, x = 3.

The number of ways to select two toothbrushes to sell from the 20 toothbrushes is:

${20\choose 2}=\frac{20!}{2!(20-2)!}=\frac{20!}{2!\times 18!}=\frac{20\times 19\times 18!}{2!\times 18!}=190$

The number of ways to select two defective toothbrushes to sell from the 3 defective toothbrushes is:

${3\choose 2}=\frac{3!}{2!(3-2)!}=\frac{3!}{2!\times 1!}=3$

Compute the probability that the first two electric toothbrushes sold are defective as follows:

P (Selling 2 defective toothbrushes) = Favorable outcomes ÷ Total no. of outcomes

$=\frac{3}{190}\\$

$=0.01579\\\approx0.016$

Thus, the probability that the first two electric toothbrushes sold are defective is 0.016.

8 0

2 years ago

Some of the students three scores is 231. If the first is 20 points more than the second, and the sum of the first two is 6 more

Aleks [24]

Answer:

The first score is 109

Step-by-step explanation:

I am assuming that in the first sentence of the question, you meant:

Sum of the students three scores is 231...

First, let the scores of the first second and third student be a, b and c respectively. We are told that:

a + b + c = 231 . . . . . . . .(1) (sum of students three scores is 231)

a = b + 20 . . . . . . . . . . . (2) (the first is 20 points more than the second)

a + b = 6c . . . . . . . . . . . .(3) (sum of the first two is 6 more times the third)

required, find a.

substituting the value of (a + b) in equation (3) into equation (1), we will have the following:

since a + b = 6c . . . (3)

a + b + c = 231 . . . . . (1), becomes,

(a + b) + c = 231

(6c) + c = 231

7c = 231 (divide both sides by 7)

c = 231 ÷ 7 = 33

∴ c = 33

Next, from equation (2), we know that a = b + 20; this can also be written as:

a - 20 = b

∴ b = a - 20 . . . . . . . (4)

Finally, putting the value of b in equation (4) and the value of c calculated above into equation 1, ( a + b + c = 231), we have the following:

a + (a - 20) + 33 = 231

(a + a) - 20 + 33 = 231

2a + 13 = 231

2a = 231 - 13 = 218

a = 218 ÷ 2 = 109

∴ a = 109

we can also calculate for 'b' by substituting for the value of 'a' in equation 4

b = a - 20 = 109 - 20 = 89.

and to test if the values of a, b and c are correct:

a + b + c = 231

109 + 89 + 33 = 231

4 0

3 years ago

Unit #2 - Lesson #7 Exit Ticket: Solve the equation shown below for the variable x. Place your answer in the answer box.

jolli1 [7]

Answer:

$x = bc + 2b$

PLEASE MARK ME AS BRAINLIEST

7 0

2 years ago

I need a bit of help with this, May you please help me? 15 points.

max2010maxim [7]

The answer is 7 feet becaise 0 opp ik

7 0

3 years ago

Read 2 more answers

Sarah works as a tutor helping out after school. She earns $10 for an hour of tutoring plus an additional $4.50 per student. How

ipn [44]

37=10+4.50x
x=number of students needed to make $37
37=10+4.50x
-10 -10
27=4.50x
/4.50 /4.50
6=x

She needs to 6 students to make $37 for an hour.

Hope it helps!

4 0

2 years ago