Assuming linear.
if k is at (3,4) and j is at (-8,7)
set. (y1,x1) and(y2,x2)
[(y2-y1),(x2-x1)]
[(-8-3),(7-4)]
distance from k to j is (-11,3)
now take coordinates of j and distance from. k->j and add them to get coordinate for L
[(-11+(-8)),(7+3)]= (-19,10)=L
Answer:
1. C. 28/54
2. A. 5/22
Step-by-step explanation:
1. Simplify each fraction to see which of the four are equal to 4/9.
2. Convert each to a decimal to see which is between 2/11 and 3/11.
In pretty sure it’s D , making each side equal to 6
Answer:
The parabola is translated down 2 units.
Step-by-step explanation:
You have the parabola f(x) = 2x² – 5x + 3
To change this parabola to f(x) = 2x² - 5x + 1, you must have performed the following calculation:
f(x) = 2x² – 5x + 3 -2= 2x² - 5x + 1 <u><em>Expresion A</em></u>
The algebraic expression of the parabola that results from translating the parabola f (x) = ax² horizontally and vertically is g (x) = a(x - p)² + q, translating in the same way as the function.
- If p> 0 and q> 0, the parabola shifts p units to the right and q units up.
- If p> 0 and q <0, the parabola shifts p units to the right and q units down.
- If p <0 and q> 0, the parabola shifts p units to the left and q units up.
- If p <0 and q <0, the parabola shifts p units to the left and q units down.
In the expression A it can be observed then that q = -2 and is less than 0. So the displacement is down 2 units.
This can also be seen graphically, in the attached image, where the red parabola corresponds to the function f(x) = 2x² – 5x + 3 and the blue one to the parabola f(x) = 2x² – 5x + 1.
In conclusion, <u><em>the parabola is translated down 2 units.</em></u>