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Colt1911 [192]
3 years ago
7

Solve the following linear system of equations using substitution.

Mathematics
2 answers:
DerKrebs [107]3 years ago
4 0

( - 1, - 8 )

since both equations give y in terms of x we can equate them

3x - 5 = 2x - 6

subtract 2x from both sides of the equation

3x - 2x - 5 = - 6

x - 5 = - 6

add 5 to both sides

x = - 6 + 5 = - 1

substitute x = - 1 into either of the 2 equations for y

y = (3 × - 1) - 5 = - 3 - 5 = - 8

solution to the system is (- 1, - 8 )



NeX [460]3 years ago
4 0

Answer:

( - 1, - 8 )

Step-by-step explanation:

just took it on edge

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ivann1987 [24]
We have the following expression:
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The correct answer is:
 
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lana66690 [7]

Answer:

x<14

Step-by-step explanation:

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3 years ago
In rhombus ABCD, AB=14 and AC=19. Find the area of the rhombus to the nearest tenth. A 190.7 B 228.3 C 195.4 D 179.8
kkurt [141]

Answer:

C

Step-by-step explanation:

The triangle ABC has two sides that are 14 and 1 side that is 19. We can use Heron's formula to Calculate ABC.

s = (a + b + c)/2

s = (14 + 14 + 19)/2 = 23.5

s - a = 23.5 - 14 = 9.5

s - b = 23.5 - 14 = 9.5

s - c = 23.5 - 19 = 4.5

=================

Area = sqrt(s * (s - a) * (s - b) * (s - c) )

Area = sqrt(23.5 * 9.5 * 9.5 * 4.5)

Area = sqrt(9543,9)

Area = 97.69

But ABC is only 1/2 the rhombus. The area is twice that amount.

Area = 2 * 97.69 = 195.4

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