The formula for the volume of a box (assuming that it is in the shape of a cube) is <u>V=B^3</u>.
12=B^3
Now, do the cube root of 12 to find each dimension, all dimensions will be equal as it is a cube.
B= about 2.29 (when doing on a calculator keep full answer and do not round)
Now to find the volume of box B, multiply each dimension by 5
5(2.29...) times 5(2.29...) times 5(2.29...)
=1,500 m^3
Hope this helps!
Answer:
i dont know i swear
Step-by-step explanation:
First and last blank im guessing is intersect or overlap the 2 in the middle should be...
It looks like the given equation is
sin(2x) - sin(2x) cos(2x) = sin(4x)
Recall the double angle identity for sine:
sin(2x) = 2 sin(x) cos(x)
which lets us rewrite the equation as
sin(2x) - sin(2x) cos(2x) = 2 sin(2x) cos(2x)
Move everything over to one side and factorize:
sin(2x) - sin(2x) cos(2x) - 2 sin(2x) cos(2x) = 0
sin(2x) - 3 sin(2x) cos(2x) = 0
sin(2x) (1 - 3 cos(2x)) = 0
Then we have two families of solutions,
sin(2x) = 0 or 1 - 3 cos(2x) = 0
sin(2x) = 0 or cos(2x) = 1/3
[2x = arcsin(0) + 2nπ or 2x = π - arcsin(0) + 2nπ]
… … … or [2x = arccos(1/3) + 2nπ or 2x = -arccos(1/3) + 2nπ]
(where n is any integer)
[2x = 2nπ or 2x = π + 2nπ]
… … … or [2x = arccos(1/3) + 2nπ or 2x = -arccos(1/3) + 2nπ]
[x = nπ or x = π/2 + nπ]
… … … or [x = 1/2 arccos(1/3) + nπ or x = -1/2 arccos(1/3) + nπ]
Calculate the mean for the three sets of data A=[1,2,3,4,5] B=[2,2,2,2,2] C=[5,7,3,11,14]
Verizon [17]
A = The mean would be 3
B = The mean would be 2
C = The mean would be 8
To calculate mean, you add up all the numbers in a set and then divide by the quantity of numbers in the set.
