Question

3k2-19=15k-1 solve by factoring

Answer 1

For this case we must factor the following expression:

$3k ^ 2-19 = 15k-1$

We manipulate algebraically, taking into account that different signs are subtracted and the sign of the major is placed:

$3k ^ 2-15k-19 + 1 = 0\\3k ^ 2-15k-18 = 0$

We divide by 3 on both sides of the equation:

$k ^ 2-5k-6 = 0$

To factor, we look for two numbers that, when multiplied, result in -6 and when added, result in -5. These numbers are -6 and +1.

$-6 + 1 = -5\\-6 * (+ 1) = - 6$

Thus, we factor the equation:

$(k-6) (k + 1) = 0$

The roots of the equation are:

$k_ {1} = 6\\k_ {2} = - 1$

ANswer:

$k_ {1} = 6\\k_ {2} = - 1$