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3 years ago

What is the range of the function for the domain?

Mathematics

1 answer:

Verdich [7]3 years ago

4 0

The domain are the x values.

The problem is saying the x value is all numbers between 4 and 8

Replace x in the equation with 4 and 8 and solve to find the range for the y values:

y =4(4) -1 = 16-1 = 15

y = 4(8) - 1 = 32-1 = 31

So Y would be between 15 and 31.

The first answer is the correct one.

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Catherine Lewiston is currently earning an annual salary of $36,080 at

Nezavi [6.7K]

Answer:

$212.31

Step-by-step explanation:

divide $36,080 by 52 weeks in a year. you get $693.84 weekly.

divide $47,120 by 52 weeks in a year. you get $906.15 weekly.

then subtract 906.15 from 693.84 and you get 212.31

5 0

3 years ago

What is the unit value of the 6 in 216?

eduard

The 6 is in the ones place the 1 is in the tens place and the 2 is in the hundreds place.

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3 years ago

Consider the expression √(√625).

const2013 [10]

Answer:

Step-by-step explanation:

Square Root - Finding a number that multiplies itself twice into the number within the square root

With this meaning, we need to find a number that multiplies itself into 625.

Finding calculations using exponents will help,

25^2 is equal to 625. Therefore $\sqrt{25}$

We are not finished, as there is another square root right after, empowering the parenthesis, so what number multiplies itself equals 25?

This would be 5, therefore $\sqrt{(\sqrt{625}) }$ is equal to 5.

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3 years ago

Please Help Timed Question. Picture provided below.

Jobisdone [24]

Answer:

17.67 mpg

Step-by-step explanation:

The fuel efficiency is given by :

$\eta=1.437+0.541\times s$

We need to find the fuel efficiency for a speed of 30 mph

Put the value of s equals 30 mph in the above equation.

$\eta=1.437+0.541\times 30\\\\\eta=17.67\ mpg$

So, the required fuel efficiency is equal to 17.67 mpg.

6 0

3 years ago

If you were to use the substitution method to solve the following system, choose the new equation after the expression equivalen

Svetllana [295]

Hello,

$\left \{ {{3x+2y=-21} \atop {x-3y=4}} \right. \\\\
 \left \{ {{3x+2y=-21} \atop {x=4+3y}} \right. \\\\
 \left \{ {{3(4+3y)+2y=-21} \atop {x=4+3y}} \right. \\\\

 \left \{ {{12+9y+2y=-21} \atop {x=4+3y}} \right. \\\\
 \left \{ {{12+11y=-21} \atop {x=4+3y}} \right. \\\\
 \left \{ {{11y=-21-12} \atop {x=4+3y}} \right. \\\\
 \left \{ {{11y=-33} \atop {x=4+3y}} \right. \\\\
 \left \{ {{y=-3} \atop {x=4+3(-3)}} \right. \\\\
 \left \{ {{y=-3} \atop {x=5}} \right. \\\\
Sol=\{(5,-3)\}\\\\



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3 0

3 years ago