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elena-14-01-66 [18.8K]
3 years ago
7

Using the number line, determine which expressions have a value that is greater than –8. Select Yes or No for each expression. l

----l----l----l----l----l----l----l----l----l----l----l----l----l----l----l----l----l----l----l----l----l----l----l----l----l----l----l----l----l----l----l----l -13 -12 -11 -10 -9 -8 -7 -6 -5 -4 -3 -2 -1 0 1 2
Yes:


-13 +1


-6 -(-6)


-4 -(-7)


-4 - 6


-2 - 11
No:

Mathematics
2 answers:
Nimfa-mama [501]3 years ago
8 0
<h3>Answer:</h3>

yes

  • -6-(-6)
  • -4-(-7)

no

  • all others
<h3>Step-by-step explanation:</h3>

Doing what the directions say is generally a good idea.

Adding a number moves to the right; subtracting a number moves to the left. Subtracting a negative number is the same as adding its opposite.

The arrowhead end of the line in the figure is the end result. Two of them end up to the right of -8, that is, greater than -8.

olasank [31]3 years ago
4 0

Answer:

Answer:

yes

-6-(-6)

-4-(-7)

no

all others

Step-by-step explanation:

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A shirt originally cost $50.97, but it is on sale for $40.78. What is the percentage decrease of the price of the shirt? If nece
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Amplitude of 16 units, a period of 5 units, a vertical displacement of 3 units up and a phase shift of 2.5 units left.
allochka39001 [22]

The question is incomplete. The complete question is :

A sine function that has an amplitude of 16 units, a period of 5 units,a vertical displacement of 3 units up and a phase shift of 2.5 units left. Graph this function and show each step.

Solution :

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y = a sin (bx - c) + d

Here given :

Amplitude, a = 16

Period :   $\frac{2 \pi}{|b|} = 5$

            ⇒ $b = \frac{2\pi}{5}$

Phase shift :  $\frac{c}{b} = 2.5$

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The vertical displacement : d = 3 units up

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$y = 16 \sin \left( \frac{2 \pi}{5}x + \pi\right) + 3$

The graph is attached below.

4 0
3 years ago
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