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3 years ago

The figure in the picture is made up of 5 congruent squares. If the perimeter of the entire figure is 21.6 cm, find its area.

Mathematics

1 answer:

vovikov84 [41]3 years ago

3 0

Perimeter is length plus width so use that to help you

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The sales tax on a $24 model rocket is $1.92 what is the percent of sales tax

AleksAgata [21]

Input data

Price model rocket = $24

Tax = $1.92

What is the percent of sales tax?

Procedure

r = percent of sales tax

$r=\frac{1.92}{24}=0.08=8\text{ \%}$

The answer would be 8%

8 0

1 year ago

Miguel collected aluminum cans for recycling. He collected a total of 150 cans. If 58% of the cans he collected were soda cans h

Romashka-Z-Leto [24]

Given:

• Total number of cans collected = 150

• Percent of cans that were soda = 58%

Let's find the number of other cans he collected.

To find the number of other cans, since the percent of soda is 58%, let's find the pecent of other cans.

Percent of other cans = 100% - 58% = 42%

The percent of other cans collected was 42%.

Now, to find the number of other cans collected, let's find 42% of the total number of cans collected 150.

We have:

$42\text{ \% }\ast150\Longrightarrow0.42\times150=63$

Therefore, the number of other cans collected is 63 cans.

ANSWER:

63 cans

4 0

1 year ago

X+y=11 and 22X+15y=228

Lady_Fox [76]

X+y=11
22x+15y=228

y=11-x
22x+15y=228
22x+15(11-x)=228
22x+165-15x=228
7x+165=228
7x=63
x=9

9+y=11
y=2

The solution to the system of equations is (9,2)

6 0

3 years ago

Write a numerical expression for the verbal expression. the difference of six and two divided by four

Ilia_Sergeevich [38]

Answer:

(6-2)/4

Step-by-step explanation:

Make sure you have the parenthesis

6 0

3 years ago

One of the roots of the quadratic equation dx^2+cx+p=0 is twice the other, find the relationship between d, c and p

scZoUnD [109]

Answer:

$c^2 = 9dp$

Step-by-step explanation:

Given

$dx^2 + cx + p = 0$

Let the roots be $\alpha$ and $\beta$

So:

$\alpha = 2\beta$

Required

Determine the relationship between d, c and p

$dx^2 + cx + p = 0$

Divide through by d

$\frac{dx^2}{d} + \frac{cx}{d} + \frac{p}{d} = 0$

$x^2 + \frac{c}{d}x + \frac{p}{d} = 0$

A quadratic equation has the form:

$x^2 - (\alpha + \beta)x + \alpha \beta = 0$

So:

$x^2 - (2\beta+ \beta)x + \beta*\beta = 0$

$x^2 - (3\beta)x + \beta^2 = 0$

So, we have:

$\frac{c}{d} = -3\beta$ -- (1)

and

$\frac{p}{d} = \beta^2$ -- (2)

Make $\beta$ the subject in (1)

$\frac{c}{d} = -3\beta$

$\beta = -\frac{c}{3d}$

Substitute $\beta = -\frac{c}{3d}$ in (2)

$\frac{p}{d} = (-\frac{c}{3d})^2$

$\frac{p}{d} = \frac{c^2}{9d^2}$

Multiply both sides by d

$d * \frac{p}{d} = \frac{c^2}{9d^2}*d$

$p = \frac{c^2}{9d}$

Cross Multiply

$9dp = c^2$

$c^2 = 9dp$

Hence, the relationship between d, c and p is: $c^2 = 9dp$

8 0

3 years ago