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2 years ago

The figure in the picture is made up of 5 congruent squares. If the perimeter of the entire figure is 21.6 cm, find its area.

Mathematics

1 answer:

vovikov84 [41]2 years ago

3 0

Perimeter is length plus width so use that to help you

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If m∠APW = 20°, then the measure of ∠WPZ is

insens350 [35]

Answer:

70°

Step-by-step explanation:

A right angle is 90°. 90°-20°=70°

5 0

2 years ago

Read 2 more answers

Pick a two-digit number greater than 25. Rewrite your two-digit number as a difference of two numbers. Show how to use the ident

e-lub [12.9K]

Answer:

Step-by-step explanation:

32²=(40-8)²

=40²-2(40)(8)+8²

=1600-640+64

=1664-640

=1024

also 32²=1024

3 0

2 years ago

A television is measured by its diagonal. If the height of a 70 inch television is 42 inches, what is the width?

GenaCL600 [577]

Use the Pythagorean theorem:

70^2 = 42^2 + width^2

4900 = 1764 + width ^2

Subtract 1764 from both sides

3136 = width^2

Take the square root of both sides

Width = 56 inches

7 0

2 years ago

Answer this volume based Question. I will make uh brainliest + 50 points

Harlamova29_29 [7]

Answer:

$\huge{\purple {r= 2\times\sqrt[3]3}}$

$\huge 2\times \sqrt [3]3 = 2.88$

Step-by-step explanation:

For solid iron sphere:
radius (r) = 2 cm (Given)

Formula for $V_{sphere}$ is given as:

$V_{sphere} =\frac{4}{3}\pi r^3$

$\implies V_{sphere} =\frac{4}{3}\pi (2)^3$

$\implies V_{sphere} =\frac{32}{3}\pi \:cm^3$

For cone:
r : h = 3 : 4 (Given)
Let r = 3x & h = 4x

Formula for $V_{cone}$ is given as:

$V_{cone} =\frac{1}{3}\pi r^2h$

$\implies V_{cone} =\frac{1}{3}\pi (3x)^2(4x)$

$\implies V_{cone} =\frac{1}{3}\pi (36x^3)$

$\implies V_{cone} =12\pi x^3\: cm^3$

It is given that: iron sphere is melted and recasted in a solid right circular cone of same volume
$\implies V_{cone} = V_{sphere}$

$\implies 12\cancel{\pi} x^3= \frac{32}{3}\cancel{\pi}$

$\implies 12x^3= \frac{32}{3}$

$\implies x^3= \frac{32}{36}$

$\implies x^3= \frac{8}{9}$

$\implies x= \sqrt[3]{\frac{8}{3^2}}$

$\implies x={\frac{2}{ \sqrt[3]{3^2}}}$

$\because r = 3x$

$\implies r=3\times {\frac{2}{ \sqrt[3]{3^2}}}$

$\implies r=3\times 2(3)^{-\frac{2}{3}}$

$\implies r= 2\times (3)^{1-\frac{2}{3}}$

$\implies r= 2\times (3)^{\frac{1}{3}}$

$\implies \huge{\purple {r= 2\times\sqrt[3]3}}$
Assuming log on both sides, we find:

$log r = log (2\times \sqrt [3]3)$

$log r = log (2\times 3^{\frac{1}{3}})$

$log r = log 2+ log 3^{\frac{1}{3}}$

$log r = log 2+ \frac{1}{3}log 3$

$log r = 0.4600704139$

Taking antilog on both sides, we find:

$antilog(log r )= antilog(0.4600704139)$

$\implies r = 2.8844991406$

$\implies \huge \red{r = 2.88\: cm}$

$\implies 2\times \sqrt [3]3 = 2.88$

8 0

1 year ago

Find the equation of the line that contains the point (-1,-11) and is parallel to the line 7x+3y=10

madam [21]

Y=- \frac{7}{3} $-13 \frac{1}{3}$ .

To find the equation of a line, you need two things: the slope and the y-intercept.

The slopes of parallel lines are the same. So we can find the slope of the new line by finding the slope of the first line. To do that, we need to put it in y=mx+b format, where m is the slope. So we must rearrange the 7x+3y=10. First subtract 7x from both sides to make it look like:
$3y=10-7x$
Then divide both sides three:
b $y= \frac{10}{3} - \frac{7}{3} x$
So now that it's in y=mx+b format, we can now see that the m= - \frac{7}{3}

Now we know the m of the new equation, we need to find the b, or the y-intercept. To do this, we can plug the point we have and the m value into the y=mx+b format.
$(-11)=- \frac{-7}{3} (-1) + b$
Solving this, we can subtract 7/3 from both sides:
$-11- \frac{7}{3} = b$
Therefore, b= $-13 \frac{1}{3}$

Plugging the m= - \frac{7}{3} and the b= $-13 \frac{1}{3}$ back into the y=mx+b format, your parallel line is y=- \frac{7}{3} $-13 \frac{1}{3}$ .

5 0

2 years ago