a hyperbola with center at (0,0), with x-intercept at (4,0) and (-4,0), with b=1, and opening horizintally has the equation

In a certain game of chance, your chances of winning are 0.2. if you play the game five times and outcomes are independent, the

ikadub [295]

<span>Winning Probablity = 0.2, hence Losing Probability = 0.8 Probablity of winning atmost one time, that means win one and lose four times or lose all the times. So p(W1 or W0) = p (W1) + p(W0) Winning once W1 is equal to L4, winning zero times is losing 5 times. p(W1) = p(W1&L4) and this happens 5 times; p(W0) = p(L5); p (W1) + p(W0) = p(L4) + p(L5) p(L4) + p(L5) = (5 x 0.2 x 0.8^4) + (0.8^5) => 0.8^4 + 0.8^5 p(W1 or W0) = 0.4096 + 0.32768 = 0.7373</span>

8 0

3 years ago

-3 17/20 as a decimal

alekssr [168]

Answer:

-3.85

-3 is a whole number, it comes before the decimal point.

17/20 is a fraction so it goes on the other side.

7 0

3 years ago

What is the equation of the line perpendicular to 3x+y=6 that passes through the point (0,8)

Alekssandra [29.7K]

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$3x + y = 6$

$y = - 3x + 6$

The coefficient of x is the slope of the line , So the slope of the above equation is -3 .

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Remember from now on ,

Product of multiplying the slopes of two lines which are perpendicular to each other , is -1 .

Thus ;

$( - 3) \times (m) = - 1$

m is the slope of the line which we want.

$- 3m = - 1$

Negatives simplifies

$3m = 1$

Divide sides by 3

$\frac{3m}{3} = \frac{1}{3} \\$

$m = \frac{1}{3} \\$

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We have following equation to find the point-slope form of the linear functions :

$y - y(0) = m(x - x(0))$

x(0) and y(0) are the coordinates of the point which the line passed through.

$y - 8 = \frac{1}{3} (x - 0) \\$

$y - 8 = \frac{1}{3} x \\$

Add sides 8

$y = \frac{1}{3} x + 8 \\$

Done....

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6 0

3 years ago

If f(x)=2x^3-6x^2-16x-20f(x)=2x *3 −6x *2−16x−20 and f(5)=0, then find all of the zeros of f(x)f(x) algebraically.

mihalych1998 [28]

The zeros of the cubic function f(x) = 2x³ - 6x² - 16x - 20 are given as follows:

x = 5, x = -1 + i, x = -1 - i.

<h3>How to obtain the solutions to the equation?</h3>

The equation is defined by the rule presented as follows:

f(x) = 2x³ - 6x² - 16x - 20.

One solution for the equation is given as follows:

x = 5.

Because f(5) = 0.

Then (x - 5) is a linear factor of the function f(x), which can be written as follows:

2x³ - 6x² - 16x - 20 = (ax² + bx + c)(x - 5).

This is because the product of a linear function and a quadratic function results in a cubic function.

Now we expand the right side to begin finding the coefficients of the quadratic function that we are going to solve to find the remaining zeros:

2x³ - 6x² - 16x - 20 = = ax³ + (b - 5a)x² + (c - 5b)x - 5c.

Then these coefficients are obtained comparing the left and the right side of the equality as follows:

a = 2.

-5c = -20 -> c = 4.

b = -6 + 5a = 4.

Hence the equation is:

2x² + 4x + 4.

Using a quadratic equation calculator, the remaining zeros are given as follows:

x = -1 + i.

x = -1 - i.

More can be learned about the solutions of an equation at brainly.com/question/25896797

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8 0

1 year ago

Hitung jarak di antara titik P(7, 1) dengan titik Q(7, 8)

MaRussiya [10]

Answer:

7 units

Step-by-step explanation:

Distance between 2 points

= $\sqrt{(y1 - y2)^{2} + (x1 - x2) {}^{2} }$

Thus, distance PQ

$=\sqrt{(8 - 1)^{2} + (7 - 7)^{2} } \\ = \sqrt{7^{2} } \\ = 7$

Or you could simply take 8-1= 7 since both points have the same x-coordinate. Thus, PQ is a vertical line and the distance between them is due to the difference in their y-coordinate.

5 0

3 years ago

a hyperbola with center at (0,0), with x-intercept at (4,0) and (-4,0), with b=1, and opening horizintally has the equation​

a hyperbola with center at (0,0), with x-intercept at (4,0) and (-4,0), with b=1, and opening horizintally has the equation