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777dan777 [17]
3 years ago
5

a bout crew rowed 16kilometers downstream, with the current, in 2 hours. the return teip upstream, against the current, covered

the same distance but took 4 hours. find the crew's rowing rate in still water and the rate of the current
Mathematics
1 answer:
gtnhenbr [62]3 years ago
6 0

Solving for both velocities:

16 km / 2 hours = 8 km per hour downstream

16 km / 4 hours = 4 km per hour upsteram

bsw means boat speed in still water  cs means current speed

bsw - cs = 4 km per hour

bsw + cs = 8 km per hour

Adding both equaions:

2 bsw = 12 km per hour

boat speed = 6 km per hour

bsw + cs = 8  then

current speed = 2 km per hour

Source:  1728.com/veloccal.htm


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7 0
3 years ago
State the conclusion based on the results of the test. The standard deviationstandard deviation inin the pressure required to op
inysia [295]

Answer:

<u>B. There is sufficient evidence that the mean of the pressure required to open a certain valve has changed. </u>

Step-by-step explanation:

We make this conclusion based on these reasons:

  1. We are told that the "null hypothesis was rejected" after the <em>"manager feels that the pressure variability has changed.,</em> meaning the <u>null hypothesis was the opposite of what occurred; that is to say, it is the alternate hypothesis that proved true instead.</u>
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It is based on the above reasons that the null hypothesis was rejected.

4 0
3 years ago
!!! Help ASAP please!!!!In DEF, sin D = 24/26 What is cos E?
Georgia [21]

Answer:

A

Step-by-step explanation:

Cosine is the ratio of "adjacent" to "hypotenuse"

With respect to the Angle E, the adjacent side is FE and the hypotenuse (always opposite side to 90 degree angle) is DE.

We are given DE = 26, but we need FE. We will solve for FE using Pythagorean Theorem, which tells us:

leg^2 + another leg^2 = hypotenuse^2

So, we will have:

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Now, we solve for FE:

10^2 + FE^2 = 26^2\\100+FE^2=676\\FE^2=576\\FE=24

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Cos(E) = adj/hyp = 24/26

Correct answer is A

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