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r-ruslan [8.4K]
3 years ago
9

3x -2 > -11 (The > has an underscore under it)

Mathematics
1 answer:
user100 [1]3 years ago
7 0

3x-2\geq-11

3x\geq-9

x\geq-3

x\in[-3, \infty)

Hope this helps.

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Amiraneli [1.4K]

Answer:

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Step-by-step explanation:

Given

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Step 1 : open the bracket with -5x^4

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Hint: - * - = +

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Hint: - * + = -

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(x is always raise to the power of 1 but we don't write it or less it is greater than 1 e.g. 2 , 3 ,4, ..........)

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Hint: - *- = +

Let's combine the answers

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We can look for a factor that can go through as in that can divide all without a reminder

Factors of

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1 * 15

20 - 4 *5

2 *10

1 * 20

10 - 2*5

1 * 10

Since the factor of 5 is common in all, so we are using 5 to divide through

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Using 5 to divide through

15x^6 / 5 - 20x^5 / 5 + 10x^4 / 5

= 3x^6 - 4x^5 + 2x^4

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Answer:

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