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sergij07 [2.7K]
2 years ago
13

D=vt-(1/2)at^2 to find a. In the formula, d is displacement, v is final velocity, a is acceleration, and t is time

Mathematics
1 answer:
larisa86 [58]2 years ago
3 0

Answer:

  a = 2(vt -d)/t^2

Step-by-step explanation:

Add the term containing "a":

  d + a(t^2/2) = vt

Subtract d:

  a(t^2/2) = vt -d

Multiply by the inverse of the coefficient of "a":

  a = 2(vt -d)/t^2

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Joe earns $14 an hour and Blaine earns $18 per hour. Joe receives a raise of $1.75 every six months, and Blaine receives a raise
Katarina [22]

After 4 interval of six months, Joe to earn same hourly rate as Blaine

<em><u>Solution:</u></em>

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Amount earned by Joe = $ 14 per hour

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<em><u>Joe receives a raise of $1.75 every six months</u></em>

Therefore,

Joe earning: 14 + 1.75(number of six month intervals)

Equation for Joe earning: 14 + 1.75x ------- eqn 1

<em><u>Blaine receives a raise of $0.75 every six months</u></em>

Therefore,

Blaine earning: 18 + 0.75(number of six month intervals)

Equation for Blaine earning: 18 + 0.75x ------------ eqn 2

The number of six-month intervals it will take Joe to earn the same hourly rate as Blaine,

Eqn 1 must be equal to eqn 2

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