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oee [108]
2 years ago
10

Helppppopleaseee????

Mathematics
1 answer:
rosijanka [135]2 years ago
7 0

Answer:

LQ = 5

Median = 6

Step-by-step explanation:

\frac{n+1}{2} gives us 5.5, so we do the average of position 5 and 6. This gives us 6, so the median is 6.

Now we find the median of the bottom half of the numbers, which is 5, so the LQ is 5.

Now we find the median of the upper half of the numbers, which is 7, so the UQ is 7.

You might be interested in
Jeffery earned $65 doing yard work. He bought a pair of jeans for $31.25 and a sweat shirt for $16.50. He set aside the money le
erastova [34]

Answer:

Step-by-step explanation:

65.00 - 31.25 - 16.50 = $17.25

4 0
3 years ago
Solve the system of equation
nikdorinn [45]

Answer:

So the Point of intersection is (-4,-2)

Which is option A

Step-by-step explanation:

The given system of equations is

-0.1x - 0.8y = 2              ...................(i)

0.6x - 0.5y = -1.4           ...................(ii)

Let us take equation (i) and use method of substitution for solving it

the equation (i) is

-0.1 x - 0.8y = 2

Adding 0.8y on both sides

-0.1 x + 0.8 y - 0.8 y = 2 + 0.8 y

-0.1 x = 2 + 0.8 y

Dividing both sides -0.1

\frac{-0.1 x}{-0.1}=\frac{0.8 y}{-0.1}+\frac{2}{-0.1}

x = -8 y - 20                     ..........................(iii)

Now we will use this value and put it into equation (ii) to find the value of y

Equation (ii) is

0.6 x - 0.5 y = -1.4

Put value of x

0.6(-8 y - 20) - 0.5 y =-1.4

It becomes

-4.8 y - 12 - 0.5 y = -1.4

adding 12 on both sides

-4.8 y - 0.5 y - 12 + 12 = -1.4 + 12

it becomes by solving

-5.3 y = 10.6

Dividing both sides by -5.3

\frac{-5.3*y}{-5.3}=\frac{10.6}{-5.3}

So

y = -2

Now we have the value of y putting it in equation (iii)

Equation (iii) is

x = -8 y - 20    

Putting value of y

x = -8*(-2) - 20

x = 16-20

x=-4

So the Point of intersection is (-4,-2)

7 0
3 years ago
The mailing list of an agency that markets scuba-diving trips to the Florida Keys contains 78% males and 22% females. The agency
choli [55]

Answer:

a) 0.98% probability that 17 of the 29 people are men.

b) 3.86% probability that the first woman is reached on the 8th call

Step-by-step explanation:

For each person chosen by the agency, there are only two possible outcomes. Either it is a man, or it is a woman. The probability of selecting a man or a women in each trial is independent from other trials. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

(a) What is the probability that 17 of the 29 people are men?

This is P(X = 17) when n = 29, p = 0.78. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 17) = C_{29,17}.(0.78)^{17}.(0.22)^{12} = 0.0098

0.98% probability that 17 of the 29 people are men.

(b) What is the probability that the first woman is reached on the 8th call?

On the first 7 trials, all men, each with a 78% probability.

On the 8th trial, a women, with a 22% probability. So

P = (0.78)^{7}*0.22 = 0.0386

3.86% probability that the first woman is reached on the 8th call

4 0
3 years ago
HELP WITH THIS NUMBER PROBLEM PLZ:)
salantis [7]
I believe you would take 127.5 and divide it by 8.5, try that and see if that works, hope this helps!
3 0
4 years ago
Read 2 more answers
Someone know how to do this?: 6x2+18x=0
Crazy boy [7]
The answer to the question is: Yes.

Explanation:  It can be solved by following exactly the same procedures
that solved the other two questions that you posted within the past 15 minutes.

Since I'm here already, here is the solution to this one:

6x² + 18x = 0

Divide each side of the equation by 6 :

x² + 3x = 0

Factor the left side:

x(x+ 3) = 0

This statement is true if x=0 or if x=3.

The solution to this one is even the same as the solution to the last one you posted.
You really ought to take a break, go back, review the solutions you've been given,
and try to solve a few on your own.
4 0
3 years ago
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