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3 years ago

Greatest to least: 0.5, -5 1/9, -7.1, 0.9

Mathematics

2 answers:

tresset_1 [31]3 years ago

8 0

Answer:

The answer is -7.1, -5, 1/9, 0.5, 0.9

Step-by-step explanation:

dedylja [7]3 years ago

7 0

Answer:

-7.1,-5 ,1/9,0.5,0.9

Step-by-step explanation:

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What is the transformation?

disa [49]

Answer:

horizontal shift left 5

Step-by-step explanation:

6 0

3 years ago

Calculus Problem

Roman55 [17]

The two parabolas intersect for

$8-x^2 = x^2 \implies 2x^2 = 8 \implies x^2 = 4 \implies x=\pm2$

and so the base of each solid is the set

$B = \left\{(x,y) \,:\, -2\le x\le2 \text{ and } x^2 \le y \le 8-x^2\right\}$

The side length of each cross section that coincides with B is equal to the vertical distance between the two parabolas, $|x^2-(8-x^2)| = 2|x^2-4|$ . But since -2 ≤ x ≤ 2, this reduces to $2(x^2-4)$ .

a. Square cross sections will contribute a volume of

$\left(2(x^2-4)\right)^2 \, \Delta x = 4(x^2-4)^2 \, \Delta x$

where ∆x is the thickness of the section. Then the volume would be

$\displaystyle \int_{-2}^2 4(x^2-4)^2 \, dx = 8 \int_0^2 (x^2-4)^2 \, dx \\\\ = 8 \int_0^2 (x^4-8x^2+16) \, dx \\\\ = 8 \left(\frac{2^5}5 - \frac{8\times2^3}3 + 16\times2\right) = \boxed{\frac{2048}{15}}$

where we take advantage of symmetry in the first line.

b. For a semicircle, the side length we found earlier corresponds to diameter. Each semicircular cross section will contribute a volume of

$\dfrac\pi8 \left(2(x^2-4)\right)^2 \, \Delta x = \dfrac\pi2 (x^2-4)^2 \, \Delta x$

We end up with the same integral as before except for the leading constant:

$\displaystyle \int_{-2}^2 \frac\pi2 (x^2-4)^2 \, dx = \pi \int_0^2 (x^2-4)^2 \, dx$

Using the result of part (a), the volume is

$\displaystyle \frac\pi8 \times 8 \int_0^2 (x^2-4)^2 \, dx = \boxed{\frac{256\pi}{15}}}$

c. An equilateral triangle with side length s has area √3/4 s², hence the volume of a given section is

$\dfrac{\sqrt3}4 \left(2(x^2-4)\right)^2 \, \Delta x = \sqrt3 (x^2-4)^2 \, \Delta x$

and using the result of part (a) again, the volume is

$\displaystyle \int_{-2}^2 \sqrt 3(x^2-4)^2 \, dx = \frac{\sqrt3}4 \times 8 \int_0^2 (x^2-4)^2 \, dx = \boxed{\frac{512}{5\sqrt3}}$

7 0

2 years ago

Each leg of a 45°-45°-90° triangle measures 12 cm what is the hypoyenuse

lubasha [3.4K]

To find the hypotenuse in a 45-45-90 triangle multiply the legs by $\sqrt{2}$
So...
The leg is 12 the hypotenuse is 12 $\sqrt{12}$

5 0

2 years ago

For how many positive values of n are both n3 and 3n four-digit integers?

AVprozaik [17]

Answer:

No positive value of n

Step-by-step explanation:

we have to find out for how many positive values of n are both

$n^3 , 3^n$ our-digit integers

Let us consider first cube

we get 4digit lowest number is 1000 and it has cube root as 10.

Thus 10 is the least integer which satisfies four digits for cube.

The highest integer is 9999 and it has cube root as 21.54

or 21 the highest integer.

Considering 3^n we get,

3^10 is having 5 digits and also 3^21

Thus there is no positive value of n which satisfy that both n cube and 3 power n are four digits.

5 0

3 years ago

A farmer knows that a crop she is growing requires 24 kg of fertilizer throughout the season. She has a measuring flask which wh

Papessa [141]

Answer:

48 times

Step-by-step explanation:

From the above question, we know that:

2 times = 1 kg of fertilizer

A crop requires 24 kg of fertilizer

Hence:

1 kg of fertilizer = 2 times

24 kg of fertilizer = x

Cross Multiply

x = 24 kg × 2 times/1 kg

x = 48 times

She need to fill the flask 48 times to make the required amount of fertilizer for the crop

8 0

2 years ago