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4 years ago

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Identify the algebraic property of equality. If 6 = 60, then = 10. Group of answer choices Substitution Property of Equality Div

ision Property of Equality Transitive Property of Equality Additive Property of Equality

1 answer:

GuDViN [60]4 years ago

5 0

Answer:

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The table shows a pattern of exponents.<br><br> What is the pattern as the exponents decrease?

Marrrta [24]

Answer:

Option C is correct.

Step-by-step explanation:

We need to find the pattern as the exponent decreases.

the first value in the table is 125.

if we divide 125 by 5 i.e 125/5 we get 25

the next value in the table is 25

if we divide 25 by 5 i.e 25/5 we get 5

the next value in the table is 5

if we divide 5 by 5 i.e 5/5 we get 1

the next value in the table is 1

if we divide 1 by 5 i.e 1/5 we get 1/5

the next value in the table is 1/5

if we divide 1/5 by 5 i.e 1/5*5 we get 1/25

the next value in the table is 1/25

So, the pattern is if we divide the previous value by 5 we get the next value in the table.

So, Option C is correct.

5 0

3 years ago

Read 2 more answers

Solve the equation. Check your answer.<br> 8=t -8.5

Kay [80]

Answer:

t= 16.5

Step-by-step explanation:

See the steps below:)

6 0

3 years ago

Helppppppppppppppppppppppppppppp

natita [175]

Answer:

Step-by-step explanation:

4=y/8+1

rewrite equation

y/8 + 1 = 4

move all terms not containing y to the right of the equation

y/8 = 3

multiply both sides of the equation by 8

8 x y/8 = 8 x 3

simplify both sides of the equation.

y = 24

4 0

3 years ago

Read 2 more answers

The weights of certain machine components are normally distributed with a mean of 8.04 g and a standard deviation of 0.08 g. Fin

NISA [10]

Answer:

The bottom 3 is separated by weight 7.8896 g and the top 3 is separated by weight 8.1904 g.

Step-by-step explanation:

We are given that

Mean, $\mu=8.04 g$

Standard deviation, $\sigma=0.08g$

We have to find the two weights that separate the top 3% and the bottom 3%.

Let x be the weight of machine components

$P(Xx_2)=0.03$

$P(X$

=0.03

From z- table we get

$P(Z1.88)=0.03$

Therefore, we get

$\frac{x_1-8.04}{0.08}=-1.88$

$x_1-8.04=-1.88\times 0.08$

$x_1=-1.88\times 0.08+8.04$

$x_1=7.8896$

$\frac{x_2-8.04}{0.08}=1.88$

$x_2=1.88\times 0.08+8.04$

$x_2=8.1904$

Hence, the bottom 3 is separated by weight 7.8896 g and the top 3 is separated by weight 8.1904 g.

5 0

3 years ago

10^4/888x7<br> A.77.82<br> B78.50<br> C. 80<br> D.non of the above

labwork [276]

Answer is a hope it helps

6 0

3 years ago