2x + 4(x - 1) = 2 + 4x
2x + 4x - 4 = 2 + 4x
6x - 4 = 2 + 4x
6x - 4x = 2 + 4
2x = 6
x = 3........there is 1 solution
25 - x = 15 - (3x + 10)
25 - x = 15 - 3x - 10
25 - x = -3x + 5
3x - x = 5 - 25
2x = - 20
x = -20/2
x = -10.....there is 1 solution
4x = 2x + 2x + 5(x - x)
4x = 4x + 5x - 5x
4x = 4x......this has infinite solutions
learn this...
if ur equation ends in a variable equaling a number, then there is one solution.
if ur equation ends in something not equal, like 2 = 4, or 4 = 6, then there is 0 solutions.
if ur equation ends in something equal to something,(the same) like 2 = 2, or 4x = 4x, then there is infinite solutions
Answer:
C & D
Step-by-step explanation:
x² + 3x - 3 = 0
a = co efficient of x² = 1
b= co efficient of x = 3
c = constant = -3
roots = (-b ± 
)/2a
= (-3±![\sqrt{3^{2}-4*1*[-3]}](https://tex.z-dn.net/?f=%5Csqrt%7B3%5E%7B2%7D-4%2A1%2A%5B-3%5D%7D)
)/2*1
= (-3±
)/2
= (-3±√21)/2
One half subtracted by one fourth is one fourth.
1/2 - 1/4 = 1/4
9514 1404 393
Answer:
23, 49
Step-by-step explanation:
Let s represent the smaller of the two numbers. Then the larger is s+26, and the sum is ...
s + (s+26) = 72
2s = 72 -26
s = (72 -26)/2 = 23
Then the larger number is
s +26 = 49
The two numbers are 23 and 49.
_____
The reason we wrote the solution this way is to show you that the smaller number is half the difference between the given sum (72) and difference (26). This is the generic solution to a "sum and difference" problem. The smaller number is always half the difference of the give sum and difference. (Similarly, the larger is always half the sum of the given sum and difference.)
That is, the two numbers are always half the sum ± half the difference:
72/2 ± 26/2 = {36+13, 36-13} = {49, 23}
