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Lady_Fox [76]
3 years ago
9

The function f(x) is shown in this graph.

Mathematics
1 answer:
mars1129 [50]3 years ago
7 0

Answer:

D. The slope of f(x) is less than the slope of g(x).

Step-by-step explanation:

✔️Slope of f(x):

Using two points on the line, (0, 2) and (1, -1),

Slope (m) = change in y/change in x

Slope (m) = (-1 - 2)/(1 - 0) = -3/1 = -3

Slope of f(x) = -3

✔️Slope of g(x) = -5x - 6:

The slope of g(x) is -5.

Therefore f(x) has a lesser absolute slope value (3) compared to the absolute slope value of g(x) (5).

Thus, D. the slope of f(x) is less than the slope of g(x).

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<em>Answer:</em>

Complete proof is written below.

Facts and explanation about the segments shown in question :

  1. As BC = EF is a given statement in the question
  2. AB + BC = AC because the definition of betweenness gives us a clear idea that if a point B is between points A and C, then the length of AB and the length of BC is equal to the length of AC. Also according to Segment addition postulate, AB + BC = AC. For example, if AB = 5 and BC= 7 then AC = AB + BC → AC = 12
  3. AC > BC because the Parts Theorem (Segments) mentions that if B is a point on AC between A and C, then AC > BC and AC>AB. So, if we observe the question figure, we can realize that point B lies on the segment AC between points A and C.
  4. AC > EF because BC is equal to EF and if AC>BC, then it must be true that the length of AC must greater than the length segment EF.

Below is the complete proof of the observation given in the question:

<em />

<em>STATEMENT                              REASON  </em>

___________________________________________________

1. BC = EF                                    1. Given

2. AB + BC = AC                         2. Betweenness

3. AC > BC                                   3. Def. of segment inequality

4. AC > EF                                   4. Def. of congruent segments

<em />

<em>Keywords: statement, length, reason, proof</em>

<em> Learn more about proof from brainly.com/question/13005321</em>

<em> #learnwithBrainly</em>

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