Diagonals of rhombus are perpendicular
area is (1/2)*d1 * d2 where d1 and d2 are the diagonal lengths
draw the diagonals on your rhombus and you will see a 30-60-90 triangle and then figure
sides will be 6 , 6√3 . 12
so d1 is 2*6 = 12
and d2 is 2*6√3 = 12√3
and area = (1/2)*12*12√3
= 72√3 square cm.
Answer:
The first one because i did the math $2.35 multiplyed by 6 equals $14.10
The general equation of a parabola is y=ax^2+bx+c At the y-intercept, x=0 and y= -8: -8 = a(0)^2 + b(0) + c. Thus, c = -8. So, our equation becomes
y = ax^2 + bx - 8. Next, substitute -1.5 for x and -12.5 for y. Then,
-12.5 = a(-1.5)^2 + b(-1.5) - 8. This simplifies to -4.5 = a(2.25) - 1.5b.
Next, take advantage of the info that the vertex is at x= -1.5.
The formula for the vertex is x=-b/(2a). Letting this formula = -1.5,
-1.5 = -b/(2a). We can then solve for b: 1.5 = b/(2a), or 3a = b.
Now go back to the equation we derived previously: -4.5 = a(2.25) - 1.5b.
Substitute 3a for b:
-4.5 = a(2.25) - 1.5(3a). Then -4.5 = -2.25a, and a = 4.5/2.25 = 2.
Last, substitute a = 2 into 3a=b to determine the value of b.
b=3(2) = 6.
Therefore, your equation is y=2x^2 + 6x - 8.
Check this result. Substitute the coordinates of the vertex (-1.5,-12.5) into this equation. Is the equation still true? If so, your equation correctly represents this parabola.
Can you show the list of ingredients?
The numbers are 109 and 327. Hope it helps!
