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Rama09 [41]
2 years ago
5

What is the sum of the measures of the angles of this 9-sided polygon?

Mathematics
2 answers:
andrezito [222]2 years ago
8 0

Answer:

the answer is 1260 or B on edge

Step-by-step explanation:

toes are on fire on a Tuesday thank you for coming to my TED talk

Alex787 [66]2 years ago
7 0

Answer:

it is B

Step-by-step explanation:

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What is the general term equation, an, for the arithmetic sequence 5, 1, â3, â7, . . . , and what is the 21st term of this seque
Valentin [98]
Hello :

the nth term ( general term  of an arithmetic sequence is :

An =A1+(n-1)d   ....a common difference is : d , A1 : the first terme
A1 = 5    and : d = 1 - 5 = - 4    n = 21
A21 = 5 + (21 -1)(-4)
A21 = 5 - 80 = -75

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3 0
3 years ago
Find the area of a triangle with a base of 7.5 m and a height of 4*
oksian1 [2.3K]

Answer:

15 units²

Step-by-step explanation:

Hi there!

A=\displaystyle\frac{1}{2} bh where <em>b</em> is the base and <em>h</em> is the height

Plug in the base (7.5) and height (4):

A=\displaystyle\frac{1}{2} (7.5)(4)\\\\A=\displaystyle\frac{1}{2} (30)\\\\A=15

Therefore, the area of the triangle is 15 units².

I hope this helps!

8 0
3 years ago
The area of the composite figure is ______ square millimeters.
leonid [27]

Answer:

i believe its 110mm

Step-by-step explanation:

3 0
2 years ago
Select "Growth" or "Decay" to classify each function.
allochka39001 [22]

1. The growth rate equation has a general form of:

y = A (r)^t

The function is growth when r≥1, and it is a decay when r<1. Therefore:

y=200(0.5)^2t                    --> Decay

y=1/2(2.5)^t/6                  --> Growth

y=(0.65)^t/4                       --> Decay

 

2. We rewrite the given equation (1/3)^d−5 = 81

 

Take the log of both sides:

(d – 5) log(1/3) = log 81

d – 5 = log 81 / log(1/3)

d – 5 = - 4

 

Multiply both sides by negative 1:

- d + 5 = 4

So the answer is D

5 0
3 years ago
How do I write 974 in expanded form
igor_vitrenko [27]
Here is 974 in expanded form
900+70+4 =974
8 0
3 years ago
Read 2 more answers
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