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Romashka-Z-Leto [24]
3 years ago
6

How do you find the measures of different angles?

Mathematics
1 answer:
xxMikexx [17]3 years ago
4 0

You could u a protracter (sorry if i miss spelled it) to get the angle or if it is a right angle, then u know it is 90 degrees.


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In ABC, if the lengths of sides a and c are 8 centimeters and 16 centimeters, respectively, and the measure of C is 35 degrees,
Simora [160]

Answer:

∠ A ≈ 16.67°

Step-by-step explanation:

Using the Sine rule in Δ ABC

\frac{a}{sinA} = \frac{c}{sinC} , substitute values

\frac{8}{sinA} = \frac{16}{sin35} ( cross- multiply )

16 sinA = 8 sin35° ( divide both sides by 16 )

sin A = \frac{8sin35}{16} , thus

∠ A = sin^{-1} ( \frac{8sin35}{16} ) ≈ 16.67° ( to 2 dec. places )

8 0
3 years ago
Select the correct answer.
Virty [35]

Answer:The answer is B

Step-by-step explanation:

8 0
3 years ago
For the functions u(t) = 8t – 14 and<br> s(t) = t2– 16, what is s (u (3))?
hjlf

Answer:

Step-by-step explanation:

u(3) = 8(3) - 14 = 24 - 14 = 10

s(10) = 10^2 - 16 = 100 - 16 = 84

6 0
3 years ago
Becky Anderson must pay a lump sum of $6000 in 5 yr. If only $5000 is available to deposit right now, what annual interest rate
34kurt

Hello!

Out equation is: A=P(1+\frac{r}{n} )^t^n

A= 6000

P=5000

N=1

T=5

R= What we are trying to find

This means we will have 6000=5000(1+r)^5

Divide both sides by 5000:

\frac{6000}{5000} = (1+r)^5

Move the power to the other side by rooting both sides:

\frac{6000}{5000} ^1^/^5 = 1+r

Subtract 1 from both sides:

\frac{6000}{5000} ^1^/^5 -1 = r

Now we just need to calculate: R = 0.03713728...

I don't know how many decimal places you can have, but I will round to 2. This will give you an Interest Rate of 3.71%.

I hope this helps! :)

6 0
3 years ago
Read 2 more answers
Help please! Thankyou
Soloha48 [4]

Answer:

Thus, option A is correct.

Explanation:

<u>match the proportions</u>

  • $240,000 → 60%
  • x → 100%

<u>set up a equation:</u>

\sf \dfrac{60}{100}  = \dfrac{240,000}{x}

\sf x = \$400,000

4 0
3 years ago
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