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2 years ago

Help please! Thankyou

Mathematics

1 answer:

Soloha48 [4]2 years ago

4 0

Answer:

Thus, option A is correct.

Explanation:

<u>match the proportions</u>

$240,000 → 60%

x → 100%

<u>set up a equation:</u>

$\sf \dfrac{60}{100} = \dfrac{240,000}{x}$

$\sf x = \$400,000$

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Answer:

The farmer should expect to LOSE 10 pounds of soybeans per acre per year

Step-by-step explanation:

f(x)=-x^2 + 20x + 100

just find how many soybeans his land will yield (per acre) after 10 and 20 years:

After 10: 200 pounds of soybeans/acre

After 20: 100 pounds of soybeans/acre

Because 10 years have passed and they lost 100 pounds of soybean production per acre, the farmer should expect to lose 10 pounds of soybeans per acre per year (-10 pounds of soybeans per acre/year)

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2 years ago

Why is -a² is always negative (a ≠ 0) and why is (-a)² is always positive?

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Regardless of the sign of $a$ , we have $a\cdot a=a^2\ge0$ (never negative). But multiplying by -1 makes it negative.

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3 years ago

One watering system needs about three times as long to complete a job as another warning system when both systems operate at the

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Answer:

One watering system requires 36 minutes to complete the job alone while another watering system requires 12 minutes to complete the job alone.

Step-by-step explanation:

Given:

Both the system can complete the job = 9 minutes

We need find the time required by each system to do the job.

Solution:

Let the time required by another watering system to complete the job be 'x' mins.

Now given:

One watering system needs about three times as long to complete a job as another watering system.

Time required by one watering system = $3x$

Rate to complete the job by another watering system = $\frac{1}{x}\ job/min$

Rate to complete the job by One watering system = $\frac{1}{3x}\ job/min$

Rate at which both can complete the job = $\frac{1}{9}\ job/min$

So we can say that;

Rate at which both can complete the job is equal to sum of Rate to complete the job by another watering system and Rate to complete the job by One watering system.

framing in equation form we get;

$\frac{1}{x}+\frac{1}{3x}=\frac19$

Now taking LCM to make the denominator common we get;

$\frac{1\times3}{x\times 3}+\frac{1\times1}{3x\times1}=\frac19\\\\\frac{3}{3x}+\frac{1}{3x}=\frac19\\\\\frac{3+1}{3x}=\frac{1}{9}\\\\\frac{4}{3x}=\frac{1}{9}$

By Cross multiplication we get;

$4\times9 =3x\\\\3x =36$

Dividing both side by 3 we get;

$\frac{3x}{3}=\frac{36}{3}\\\\x=12\ min$

Time required by One watering system = $3x =3\times 12 =36\ min$

Hence One watering system requires 36 minutes to complete the job alone while another watering system requires 12 minutes to complete the job alone.

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3 years ago