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Lynna [10]
4 years ago
9

A school conducts 27 test and 36 weeks assume the school conducts test at a constant rate what is the slope of the line that rep

resents the number of tests on the Y axis and the time in weeks on the X axis
A: 3/4
B: 4/3
C: 3
D: 4
Mathematics
2 answers:
Katarina [22]4 years ago
8 0

Answer:

3/4

Step-by-step explanation:

I got it right.

frosja888 [35]4 years ago
6 0
Slope equals rise over run. Rise is referring to y values and run is referring to X values. so if they say tests are the Y axis then you use 27 as the rise and 36 as the run. once you have the fraction it is simply reducing the fraction.
27/36= 9/12 = 3/4
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Carlos has $8.48. Alyssa has $4.14. How much money does Carlos need to get Alyssa so each of them has the same amount of money?​
Margaret [11]

Answer:

the answer is $2.17

Step-by-step explanation:

Subtract 8.48 from 4.14 to get 4.34 and then divide that by two to get 2.17. You add 2.17 to 4.14 to get 6.31 and subtract 2.17 from 8.48 to get 6.31.

Hope this helps!

3 0
3 years ago
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yawa3891 [41]

Answer:

Step-by-step explanation:

it should add up to 360°

360=135 + 120 + 7x-64+5x-4+3x+31+4x+15+6x-8     (seems like too much huh)

360=225+25x  ( much better just add the x terms and the constants together)

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4 0
3 years ago
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Sidana [21]
Number of outcomes when flipping a coin = 2
Favorable outcome is landing on head.
So,number of favorable outcomes = 1

Probability of getting a head when flipping a coin = \frac{1}{2}

Number of outcomes when rolling a dice = 6
Favorable outcomes are rolling 4,5 or 6.
So,number of favorable outcomes = 3

Probability of getting 4 or a bigger number when rolling a dice = \frac{3}{6}= \frac{1}{2}

Thus the probability of getting a head when flipping a coin and getting a number equal to or greater than 4 when a dice is rolled = \frac{1}{2}* \frac{1}{2} = \frac{1}{4}

So, option A gives the correct answer
6 0
4 years ago
Read 2 more answers
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aleksley [76]

Answer:

17.5

plsss mark brainliestt

Step-by-step explanation:

10÷4=2.5

7×2.5=17.5

7 0
3 years ago
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Which figure is the image produced by applying the composition t 0,3 r 0,90 to figure R?
Maksim231197 [3]

Answer:

Option A is correct

The only figure after composition of t_{0 , 3} (r_{0,90^{\circ}}) to figure R is Figure H

Step-by-step explanation:

From the given figure in R;

The coordinates in Figure R ;

(1 , -1) , (2, -2) ,(4, -2) ( 0, -4)

Composite function defined as when one function is substituted into another function.

To Apply the composition t_{0 , 3} (r_{0,90^{\circ}}) to figure R;

First apply the Reflection r_{0, 90^{\circ}} in Figure R;

The rule of reflection is given by:

(x,y) \rightarrow (-y,x)

By applying the rule of reflection in Figure R ,

then, the coordinates becomes;

(1 , -1) \rightarrow (1, 1)

(2 , -2) \rightarrow (2, 2)

(4 , -2) \rightarrow (2, 4)

(0, -4) \rightarrow (4, 0)

Now, apply the translation t_{0,3}

Translation : It is a type of transformation that moves each point in a figure the same distance in the same direction.

then,

the rule of translation is:

(x,y) \rightarrow (x+0,y+3)

Apply the rule of translation on coordinates (1,1) , (2,2),  (2,4) and (4,0)

then

(1 , 1) \rightarrow (1+0 1+3) =(1,4)

(2, 2) \rightarrow (2+0 2+3) =(2, 5)

(2, 4) \rightarrow (2+0 4+3) =(2 ,7) and

(4, 0) \rightarrow (4+0 0+3) =(4 ,3)

Then, the only figure after composition of t_{0 , 3} (r_{0,90^{\circ}}) to figure R is Figure H





7 0
4 years ago
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