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skad [1K]
3 years ago
7

Which of the following is listed from smallest to largest? Possible answers are,

Mathematics
1 answer:
yan [13]3 years ago
3 0

Answer:

Step-by-step explanation:

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5th grade math help me plz
kakasveta [241]

Answer:

748917

Step-by-step explanation:

7 0
4 years ago
Read 2 more answers
PLZ HELP!!!!
valentina_108 [34]
The expression for the area in terms of the width is:
A
=
w
2
+
7
w
When
w
=
12
, the area is
228
units.
Explanation:
We know that the formula for the area of a rectangle is:
Area = length x width
A
=
l
w
In this specific case, though, we are told that the length is
7
units greater than the width:
l
=
w
+
7
We can substitute this value for
l
into our area formula, and then there will be only one variable on the right-hand side:
A
=
l
w
=
(
w
+
7
)
w
=
w
2
+
7
w
This expression is the answer to the final sentence in the question, asking us to write an expression for
A
in terms only of
w
.
Now we can use our expression to find the area in the situation where
w
=
12
:
A
=
w
2
+
7
w
=
12
2
+
7
×
12
=
144
+
84
=
228
units
4 0
3 years ago
Type the correct answer in each box. Use numerals instead of words. If necessary, use for the fraction bar(s).
butalik [34]

a= 7 , b=9 , c=4 because if you take an example like

\sqrt{x}  = {x}^{ \frac{1}{2} }

so the a=x b=1 c=2

6 0
3 years ago
Read 2 more answers
The sum of two numbers is 33 and thier difference is 2 find the number
sammy [17]

Answer:

17.5 + 15.5

Step-by-step explanation:

17+ 15 = 32

.5 + .5 = 1

32 + 1 = 33

6 0
3 years ago
Read 2 more answers
What is the polar form of -3+ v3i?
Softa [21]
  • z=-3+√3i
  • a=-3,b=√3

So

\\ \rm\Rrightarrow r=\sqrt{a^2+b^2}

\\ \rm\Rrightarrow r=\sqrt{(-3)^2+(\sqrt{3})^2}

\\ \rm\Rrightarrow r=\sqrt{9+3}

\\ \rm\Rrightarrow r=\sqrt{12}

\\ \rm\Rrightarrow r=2\sqrt{3}

Find theta

\\ \rm\Rrightarrow \theta=tan^{-1}(\dfrac{y}{x})

\\ \rm\Rrightarrow \theta=tan^{-1}(\dfrac{\sqrt{3}}{3})

\\ \rm\Rrightarrow \theta=tan^{-1}(\dfrac{-1}{\sqrt{3}})

\\ \rm\Rrightarrow \theta=\dfrac{5\pi}{6}

Polar form

\\ \rm\Rrightarrow r(cos\theta+isin\theta)

\\ \rm\Rrightarrow 2\sqrt{3}(cos\dfrac{5\pi}{6}+isin\dfrac{5\pi}{6})

7 0
2 years ago
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