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2 years ago

Which system of equations is represented by the graph?

1 answer:

4 0

From the given description of the graph:
rational graph with asymptotes of x equals 4 and y equals negative 1
This corresponds to
y =(-x + 10) / (x - 4)
The second description
Linear graph intersects it at negative 2, negative 2 and 5, 5
Corresponds to
y = x

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Solve for d. 6(d+1)−2d=54 Enter your answer in the box.

Solnce55 [7]

D = 12 the answer is 12

3 0

2 years ago

A circular cake with a radius of 8 inches is cut from the center into 6 equal pieces. How many inches wide, to the nearest tenth

aalyn [17]

Answer: 8.4 inches.

Step-by-step explanation:

We know that the circumference of a circle can be calculated with this formula:

$C=2\pi r$

Where "r" is the radius of the circle.

We know that the circular cake (whose radius is 8 inches) is cut from the center into 6 equal pieces. Then, you need to divide the circumference of this circular cake by 6 to find the width of the outer edge of each piece of cake.

Therefore, this is (to the nearest tenth of an inch):

$C=\frac{2\pi (8in)}{6}\\\\C=8.4in$

5 0

3 years ago

Read 2 more answers

Let represent the number of tires with low air pressure on a randomly chosen car. The probability distribution of is as follows.

Sindrei [870]

Answer:

a) $P(X=3) = 0.1$

b) $P(X\geq 3) =1-P(X$

And replacing we got:

$P(X \geq 3) = 1- [0.2+0.3+0.1]= 0.4$

c) $P(X=4) = 0.3$

d) $P(X=0) = 0.2$

e) $E(X) =0*0.2 +1*0.3+2*0.1 +3*0.1 +4*0.3= 2$

f) $E(X^2)= \sum_{i=1}^n X^2_i P(X_i)$

And replacing we got:

$E(X^2) =0^2*0.2 +1^2*0.3+2^2*0.1 +3^2*0.1 +4^2*0.3= 6.4$

And the variance would be:

$Var(X0 =E(X^2)- [E(X)]^2 = 6.4 -(2^2)= 2.4$

And the deviation:

$\sigma =\sqrt{2.4} = 1.549$

Step-by-step explanation:

We have the following distribution

x 0 1 2 3 4

P(x) 0.2 0.3 0.1 0.1 0.3

Part a

For this case:

$P(X=3) = 0.1$

Part b

We want this probability:

$P(X\geq 3) =1-P(X$

And replacing we got:

$P(X \geq 3) = 1- [0.2+0.3+0.1]= 0.4$

Part c

For this case we want this probability:

$P(X=4) = 0.3$

Part d

$P(X=0) = 0.2$

Part e

We can find the mean with this formula:

$E(X)= \sum_{i=1}^n X_i P(X_i)$

And replacing we got:

$E(X) =0*0.2 +1*0.3+2*0.1 +3*0.1 +4*0.3= 2$

Part f

We can find the second moment with this formula

$E(X^2)= \sum_{i=1}^n X^2_i P(X_i)$

And replacing we got:

$E(X^2) =0^2*0.2 +1^2*0.3+2^2*0.1 +3^2*0.1 +4^2*0.3= 6.4$

And the variance would be:

$Var(X0 =E(X^2)- [E(X)]^2 = 6.4 -(2^2)= 2.4$

And the deviation:

$\sigma =\sqrt{2.4} = 1.549$

4 0

3 years ago

How to work it out And who drove farther and how many miles farther

OlgaM077 [116]

Easy, just divide
kelly=440mi/8hr=220mi/4hr=110mi/2hr=55mi/1hr
alberto=468mi/9hr=156mi/3hr=52mi/1hr

55>52

kelly drove 55mi in 1 hour
55-52=3
she drove 3 miles more in 1 hour

5 0

2 years ago

Log (3x+1) - Log (2x+5)= 1

sleet_krkn [62]

Answer:

$\huge \red { \boxed{x = - \frac{49}{17}}}$

Step-by-step explanation:

$log(3x + 1) - log(2x + 5) = 1 \\ \\ log \: \frac{3x + 1}{2x + 5} = log \: 10..( \because \: log \: 10 = 1) \\ \\ \frac{3x + 1}{2x + 5} = 10 \\ \\ 3x + 1 = 20x + 50 \\ 3x - 20x = 50 - 1 \\ \\ - 17x = 49 \\ \\ x = \frac{49}{ - 17} \\ \\ \huge \purple{ \boxed{x = - \frac{49}{17}}} \\$

6 0

2 years ago