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Natalka [10]
3 years ago
5

Which system of equations is represented by the graph?

Mathematics
1 answer:
Aneli [31]3 years ago
4 0
From the given description of the graph:
<span>rational graph with asymptotes of x equals 4 and y equals negative 1
This corresponds to
y =(-x + 10) / (x - 4)
The second description
</span><span>Linear graph intersects it at negative 2, negative 2 and 5, 5 
Corresponds to
</span><span>y = x</span>
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An art history professor assigns letter grades on a test according to the following scheme. A: Top 13% of scores B: Scores below
madam [21]

Answer:

The numerical limits for a B grade are 81 and 89, that is, a score between 81 and 89 gets a B grade.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Scores on the test are normally distributed with a mean of 79.7 and a standard deviation of 8.4.

This means that \mu = 79.7, \sigma = 8.4

B: Scores below the top 13% and above the bottom 56%

So between the 56th percentile and the 100 - 13 = 87th percentile.

56th percentile:

X when Z has a p-value of 0.56, so X when Z = 0.15. Then

Z = \frac{X - \mu}{\sigma}

0.15 = \frac{X - 79.7}{8.4}

X - 79.7 = 0.15*8.4

X = 81

87th percentile:

X when Z has a p-value of 0.87, so X when Z = 1.13.

Z = \frac{X - \mu}{\sigma}

1.13 = \frac{X - 79.7}{8.4}

X - 79.7 = 1.13*8.4

X = 89

The numerical limits for a B grade are 81 and 89, that is, a score between 81 and 89 gets a B grade.

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Step-by-step explanation:

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