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Papessa [141]
4 years ago
12

In timra’s math class, there are 12 boys and 15 girls. What is the ratio of boys to girls in timra’s math class

Mathematics
1 answer:
Rainbow [258]4 years ago
4 0
The ratio for the class is 4:5 you must divide each by 3
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Answer:

Step-by-step explanation:

1.  The slope is -5/2

2. There is no slope for the second one it's just y=3

3. The slope is 3

4. These are perpendicular lines

5. These lines are parallel.

6. These lines are neither perpendicular nor parallel.

7. These lines are perpendicular

8.  y = 4/3x - 2

9.  y = -1/2x + 5

10. x = -1  

Hope this helps!

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3 years ago
Please answer this question
stira [4]

Graph 1: Domain = 2 <= x < 12  

Graph 1: Range = {2,4}

Graph 2: Domain = 3 <= x <= 10  

Graph 2: Range = -6 <= y <= 4

Graph 3: Domain = 4 < x < 11  

Graph 4: Range = -6 <= y < 2

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3 years ago
Help please I would appreciate it ! 10 points
Helen [10]

Answer:

B and d

Step-by-step explanation:

b and d

3 0
3 years ago
Read 2 more answers
Which ratio is the odd one out 4:20. 3:15 8:39 1:5 10:50
Oksana_A [137]

Answer:

8:39

Step-by-step explanation:

because when simplified, all the rest are 1:5

4 0
3 years ago
Find the point, M, that divides segment AB into a ratio of 2:3 if A is at (0.15) and B is at (20.0)
timama [110]

Answer:

M = (8,9)

Step-by-step explanation:

Notice that the points (0,15), and (20,0) form with the origin of coordinates (0,0),  a right angle triangle (please see attached image). This triangle has twon perpendicular sides of length 15 and 20 respectively. Therefore, we can find the length of the segment that joins points A (0,15) and B (20,0) by finding the length of the hypotenuse in a right angle triangle (with the Pythagorean Theorem):

AB=\sqrt{15^2+20^2} =\sqrt{625} =25

Now, to get a 2:3 proportion on Segment AB which is of length 25, we need to divide it in five equal parts (see the picture on the right of the attached image), and place point M at two of these divisions from point A (0,15) and along segment AB.

In order to find the appropriate location in (x,y) coordinates, we consider a smaller triangle (pictured in orange in the image) that is similar to the first larger triangle (pictured in blue). Notice that if the length of AB is 25,  each of its five equal divisions would be of length "5", and therefore two of them will render a length of "10" (which is the hypotenuse of this smaller right angle triangle.

Now, in order to find the sides of this smaller triangle (which can give us the clues on the horizontal and vertical coordinates of point M), we can use proportions.

To find the length "x" of the horizontal side , we do:

\frac{x}{10} =\frac{20}{25} \\x=\frac{10*20}{25} \\x=8

To find the length "y" of the vertical side , we do:

\frac{y}{10} =\frac{15}{25} \\y=\frac{10*15}{25} \\y=6

Then, the coordinate "x" of point M will be "8", while we can calculate the y position of point M subtracting "6" from 15 (the length of the vertical side in the original triangle). This gives us the coordinates (8,9) for point M as marked in orange in the picture.

7 0
3 years ago
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