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lidiya [134]
3 years ago
8

Help me plz and god bless :/

Mathematics
1 answer:
Lelechka [254]3 years ago
6 0

Upper quartile would be 4.5. The interquartile range could be 6.

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the answer is C

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2 years ago
Perimeter of a rectangle is 52 feet. If the length is 10 less than 2 times the width, what is the width?
ella [17]

Step-by-step explanation:

Let the width be x feet.

Therefore, length = 2x - 10

Perimeter of rectangle = 52

2(2x - 10 + x) = 52 \\ 2(3x - 10) = 52 \\ \therefore \:  3x - 10 =  \frac{52}{2} \\ \therefore \:  3x - 10 = 26\\ \therefore \:  3x = 26 + 10\\ \therefore \:  3x = 36 \\ \therefore \:  x =  \frac{36}{3} \\ \therefore \:  x =  12 \\ \purple{ \boxed{\therefore \: width \: of \: rectangle = 12 \: feet }}

6 0
3 years ago
Given the graphs of f(x) =x -7 and g(x) =-5x-1, what is the solution to the equation f() = g(x)?
lions [1.4K]

Answer:

1

Step-by-step explanation:

x-7=-5x-1

x-(-5x)-7=-1

x+5x-7=-1

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6x=6

x=6/6

x=1

8 0
2 years ago
Help:<br> <img src="https://tex.z-dn.net/?f=1.%5C%20%26x%5E4-61x%5E2%2B900%3D0%20%5C%5C%202.%20%5C%20%26%20x%5E4-25x%5E2%2B144%3
yawa3891 [41]

\bf{1) \  x^4-61x^2+900=0 }

Applying the factorization method, for example:

      \bf{ 0=(x^2)^2-61(x^2)+900=(x^2-36)(x^2-25)}

               \bf{\\ &=(x+6)(x-6)(x+5)(x-5);    }

              \bf{ x_1=6 \quad x_2=-6 \quad \ \ \ x_3=5 \quad x_4=5  }

\bf{2) \  x^4-25x^2+144=0  }

Applying the factorization method:

          \bf{0&=(x^2)^2-25(x^2)+144=(x^2-16)(x^2-9) }

             \bf{ =(x-4)(x+4)(x-3)(x+3); }

            \bf{ x_1=4 \quad x_2=-4 \quad x_3=3 \quad x_4=-3  }

7 0
1 year ago
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