Answer:
<em>(8.21, -20.79)</em>
Step-by-step explanation:
Given the simultaneous equation;

From 2;
a = 29 + b ....3
Substitute 3 into 1;

Factorize
b = -18±√18²-4(-58)/2
b = -18±√324+232/2
b = -18±√556/2
b = -18±23.58/2
b = -18-23.58/2 and -18+23.58/2
b = -41.58/2 and 5.58/2
b = -20.79 and 2.79
Since a = 29 + b
when b = -20.79
a = 29 - 20.79
a = 8.21
<em>Hence the solution to the system of equation is (8.21, -20.79)</em>
Answer:
110
Step-by-step explanation:
We can use the ratio from Fahrenheit to Celcius
32:0
Now just divide
230 ÷ 32
110
And That is your Celsius!
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Answer:
= 12
Step-by-step explanation:
{ 3 ×
- 3 } -3 × 4
Solve the brackets first
{3 × 9 - 3 } -3 × 4
{ 27 -3 } -3 × 4
24 - 3 × 4
24 - 12
= 12
Answer
a. 28˚
b. 76˚
c. 104˚
d. 56˚
Step-by-step explanation
Given,
∠BCE=28° ∠ACD=31° & line AB=AC .
According To the Question,
- a. the angle between a chord and a tangent through one of the end points of the chord is equal to the angle in the alternate segment.(Alternate Segment Theorem) Thus, ∠BAC=28°
- b. We Know The Sum Of All Angles in a triangle is 180˚, 180°-∠CAB(28°)=152° and ΔABC is an isosceles triangle, So 152°/2=76˚
thus , ∠ABC=76° .
- c. We know the Sum of all angles in a triangle is 180° and opposite angles in a cyclic quadrilateral(ABCD) add up to 180˚,
Thus, ∠ACD + ∠ACB = 31° + 76° ⇔ 107°
Now, ∠DCB + ∠DAB = 180°(Cyclic Quadrilateral opposite angle)
∠DAB = 180° - 107° ⇔ 73°
& We Know, ∠DAC+∠CAB=∠DAB ⇔ ∠DAC = 73° - 28° ⇔ 45°
Now, In Triangle ADC Sum of angles in a triangle is 180°
∠ADC = 180° - (31° + 45°) ⇔ 104˚
- d. ∠COB = 28°×2 ⇔ 56˚ , because With the Same Arc(CB) The Angle at circumference are half of the angle at the centre
For Diagram, Please Find in Attachment
Answer:
You wrote the question wrong...
m is not -16 it is -1/6 (that is a big difference)
y=mx+b
y=-1/6x+b
3 = -1/6(12) + b
3 = -2 + b
b=5
Step-by-step explanation: