For the triangle the value for w would be 11. Im not 100% sure for the other ones though. Sorry
1) Because
is a central angle,
.
Since
and
are supplementary, they form a linear pair, and thus 
5) Tangents drawn from an external common point are congruent, so CR=CP=8 and RB=BQ=4. This means that QA=11, and so PA=11 as well. Adding CP+PA, we get AC=19.
6) By the inscribed angle theorem, angle QPR measures 36 degrees.
Answer:
(x+1)²+(y-2)²= 20
Step-by-step explanation:
P = (-3,-2)
Q = (1, 6)
<u>Center (h, k)</u>
C = ((-3+1)/2 , (-2+6)/2)
C = (-2/2 , 4/2)
C = (-1 , 2)
Radius = Distance from the center to point Q
R = √((1-(-1))² + (6-(2))²)
R = √((2)² + (4)²)
R = √(4+ 16)
R = √20
Equation
(x-h)²+(y-k)²= R²
(x-(-1))²+(y-2)²= (√20)²
(x+1)²+(y-2)²= 20
y = 4x−10 ; slope m = 4
Parallel has same slope so slope of new line = 4
y = 4x + b
b = y - 4x
Passes through (1, 13)
b = 13 - 4(1)
b = 13 - 4
b = 9
Equation
y = 4x + 9
Answer:
66
Step-by-step explanation:
Find other side:
116 + x = 180
-116 -116
------------------
x = 64
Find missing triangle angle:
50 + 64 + x = 180
114 + x = 180
-114 -114
-------------------
x = 66
Hope this helped.