Ask question

Ask question

All categories

3 years ago

12

324 soldiers queued up such that the number of queues is equal to the number of soldiers in each queue. find the number of queue

s

1 answer:

Yanka [14]3 years ago

8 0

I think so answer will be 164.

You might be interested in

What is the green dashed line called?

lisov135 [29]

Answer:

axis of symetry

Step-by-step explanation:

Beast_Building on yt

6 0

3 years ago

What is 0.1% of 203.75 million?

lesya [120]

Answer:

O.1% of 203.75 million is 0.20375.

7 0

3 years ago

Read 2 more answers

Find the area of the figure.

Ivanshal [37]

Step-by-step explanation:

Area of Rectangle at the top =

Length x Width

$= 3.5 \times 3 \\ = 10.5 {mm}^{2}$

Area of Quarter- Circle = 1/4 x Area of Circle

$= \frac{1}{4} \pi {r}^{2} \\ = \frac{1}{4} \pi( {3.5}^{2} ) \\ = 3 \frac{1}{16} \pi {mm}^{2}$

Area of Rectangle at the right = Length x Width

$= 5.5 \times 3.5 \\ = 19.25 {mm}^{2}$

Total Area = Area of 2 Rectangles + Area of Quarter Circle

$= 10.5 + 3 \frac{1}{16} \pi + 19.25 \\ = 29.75 + 3 \frac{1}{16}\pi \\ = 32 \frac{13}{16}\pi {mm}^{2}$

I will leave the answer in terms of pi as I'm not sure if you need to round off your answer.

8 0

3 years ago

Mia tossed a penny, a nickel, and a dime. Which is a complete tree diagram for all possible outcomes, where H represents heads a

Novay_Z [31]

Mia tossed a penny,a nickel and a dime all possible outcomes of H is the answer C.

Step-by-step explanation:

The two possible outcomes for penny,nickel and dime is H & T.
H is for head T is for tail.
Let A {HHH,HHT,HTH,HTT,THH,THT,TTH,TTT}
Tossing a fair coin will give the above result.
S is the called the n number of outcomes that are available for a set.
Total outcome of Sample space 8.
The three diagram is like a game theory it exploits different outcome.

8 0

3 years ago

ASHA 777 [7]

Answer:

(-6,4)

Step-by-step explanation:

The equations are:

$x^2+4y^2=100\\4y-x^2=-20$

Solving for x^2 of the 2nd equation and putting that in place of x^2 in the 2nd equation we have:

$4y-x^2=-20\\x^2=4y+20\\-------\\x^2+4y^2=100\\4y+20+4y^2=100$

Now we can solve for y:

$4y+20+4y^2=100\\4y^2+4y-80=0\\y^2+y-20=0\\(y+5)(y-4)=0\\y=4,-5$

So plugging in y = 4 into an equation and solving for x, we have:

$x^2=4y+20\\x=+-\sqrt{4y+20} \\x=+-\sqrt{4(4)+20} \\x=+-\sqrt{36} \\x=6,-6$

So y = 4 corresponds to x = 6 & x = -6

The pairs would be

(6,4) & (-6,4)

<u><em>we see that (-6,4) falls in the 2nd quadrant, thus this is the solution we are looking for.</em></u>

5 0

3 years ago