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Charra [1.4K]
2 years ago
11

Select the correct answer.

Mathematics
1 answer:
Valentin [98]2 years ago
6 0

Answer: C

Step-by-step explanation:

The answer is C

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Help !! ASAP PLSS !!!
nlexa [21]

Answer:

the 3rd one x+2=5

Step-by-step explanation:

Why?

because you are going from small # to a bigger # so you know you are adding

there is 2 there and it says that it = 5

7 0
2 years ago
Molly bought 12.5 yards of fabric for $4.50 a yard to make dog beds.she uses 2.5 yards of fabric for each dog bed. She sells eac
Kay [80]
First, you need to divide 12.5/2.5= 5. After that, you need to multiply 17.50x5=87.50. So your answer is $87.50.
6 0
3 years ago
Read 2 more answers
What is 22% reduced as a fraction ??
Svet_ta [14]

Answer:

11/50

Step-by-step explanation:

22% is 22/100

So, divide 22/100 by 2 to get 11/50, which cannot be simplified any further.

3 0
3 years ago
Y =1/4x + 3<br> Y = -1<br> Help me
kap26 [50]

Y = 7  

Explication pas à pas:

x est -3 donc -3 et connectez le x.

Y = -1 / 3 (-3) +5.

Y = 1 + 5

Y = 7

7 0
3 years ago
PLEASE PEOPLE, HELP ME!! Geometry
Oksanka [162]
I use the sin rule to find the area

A=(1/2)a*b*sin(∡ab)

1) A=(1/2)*(AB)*(BC)*sin(∡B)
sin(∡B)=[2*A]/[(AB)*(BC)]

we know that
A=5√3
BC=4
AB=5
then

sin(∡B)=[2*5√3]/[(5)*(4)]=10√3/20=√3/2
(∡B)=arc sin (√3/2)= 60°

 now i use the the Law of Cosines 

c2 = a2 + b2 − 2ab cos(C)

AC²=AB²+BC²-2AB*BC*cos (∡B)

AC²=5²+4²-2*(5)*(4)*cos (60)----------- > 25+16-40*(1/2)=21

AC=√21= 4.58 cms

the answer part 1) is 4.58 cms

2) we know that

a/sinA=b/sin B=c/sinC

and

∡K=α

∡M=β

ME=b

then

b/sin(α)=KE/sin(β)=KM/sin(180-(α+β))

KE=b*sin(β)/sin(α)

A=(1/2)*(ME)*(KE)*sin(180-(α+β))

sin(180-(α+β))=sin(α+β)

A=(1/2)*(b)*(b*sin(β)/sin(α))*sin(α+β)=[(1/2)*b²*sin(β)/sin(α)]*sin(α+β)

A=[(1/2)*b²*sin(β)/sin(α)]*sin(α+β)

KE/sin(β)=KM/sin(180-(α+β))

KM=(KE/sin(β))*sin(180-(α+β))--------- > KM=(KE/sin(β))*sin(α+β)

the answers part 2) are

side KE=b*sin(β)/sin(α)
side KM=(KE/sin(β))*sin(α+β)
Area A=[(1/2)*b²*sin(β)/sin(α)]*sin(α+β)

5 0
3 years ago
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