Answer: 16 double rooms and 10 single rooms were rented.
Step-by-step explanation:
Let x represent the number of double rooms that were rented.
Let y represent the number of single rooms that were rented.
The total number of rooms rented in a day is 26. It means that
x + y = 26
A motel rents double rooms at $34 per day and single rooms at $26 per day. If all the rooms that were rented for one day cost a total of $804, it means that
34x + 26y = 804 - - - - - - - - - - -1
Substituting x = 26 - y into equation 1, it becomes
34(26 - y) + 26y = 804
884 - 34y + 26y = 804
- 34y + 26y = 804 - 884
- 8y = - 80
y = - 80/ - 8 = 10
x = 26 - y = 26 - 10
x = 16
Answer:
c = 20d + 15
Step-by-step explanation:
answer choices may help if the answer is not one of the choices; but here is the answer that it should be:
20 dollars per day is 20 times the length of rental.
15 is a cost that is added and does not change.
c = the total cost therefore:
c = 20d + 15
Answer:
Step-by-step explanation:
Depends on what you mean by multiplying by - 1. I assume you are not going to multiply the y or f(x) term by - 1.
If that is so, take an example. Suppose you have a graph that is y=x^2
That's a parabola that opens upwards and it has a line going through its focus which is a point on the +y axis.
When you multiply the right hand side by - 1, the graph you get will be y = - x^2.
That opens downward and the focus is on the - y axis.
That means that the effect of the graph is that it flips over the x axis, which I think is the third answer.
An isosceles right triangle is composed of a right angle and two congruent acute angles. In this case, 90 + 2x = 180 where x is the acute angle. x is equal to 45 degrees. Using sine law, 8/sin 90 = y / sin 45 where y is the leg of the triangle. the leg's length is equal to 4 sqrt 2.
Step-by-step explanation:
y = 3 + 8x^(³/₂), 0 ≤ x ≤ 1
dy/dx = 12√x
Arc length is:
s = ∫ ds
s = ∫₀¹ √(1 + (dy/dx)²) dx
s = ∫₀¹ √(1 + (12√x)²) dx
s = ∫₀¹ √(1 + 144x) dx
If u = 1 + 144x, then du = 144 dx.
s = 1/144 ∫ √u du
s = 1/144 (⅔ u^(³/₂))
s = 1/216 u^(³/₂)
Substitute back:
s = 1/216 (1 + 144x)^(³/₂)
Evaluate between x=0 and x=1.
s = [1/216 (1 + 144)^(³/₂)] − [1/216 (1 + 0)^(³/₂)]
s = 1/216 (145)^(³/₂) − 1/216
s = (145√145 − 1) / 216
