Answer:
<u>Do not use such labels because they may be misleading and are unethical.</u>
Explanation:
Note, there is a<u> big difference in design</u> between the two terms or labels. Lithium metal batteries are <u>non-rechargeable batteries.</u> In other words, they cannot be recharged after they run down. For example, most <em>watches, calculators, or car keys are made of </em>lithium metal batteries.
While Lithium-ion batteries (or Li-ion batteries) are <u>rechargeable batteries</u>
, and they are commonly used by<em> mobile phones, laptops, and other gadgets.</em>
<em>Therefore, </em>with such differences in mind, it may be very misleading when someone in possession of the mobile phone sees the lithium metal labels; then thinks the battery is non-rechargeable.
Answer:
True
Explanation:
<em>Professional bureaucracy</em> is considered as a combination of professionals withing a government or private organization, these professionals are relied on to achieve productivity and are involved in making major decisions or implementing major regulations that decide the future of the organization.
In other words, professional bureaucracy grants employed professionals flexibility in carrying out their responsibilities in the organization, i.e., greater control of their duties.
I believe the answer is editing group
This stage is known as fetching.
- Any operation you do in a computer, it runs a lot of codes inside it, and these codes are in binary.
- For the operation, the computer accesses the RAM memory to gather information about this process, and moves it to the CPU, in a process named as fetching.
- Thus, the stage asked in this problem is known as fetching.
A similar problem is given at brainly.com/question/21536104
Answer:
Logic for a program
Explanation:
//Here ind = index
//declare the number
number ind
number sum
number avg
number SIZE = 20
number num[SIZE] = {0,0,0,0,0,0,0,0,0,0
,0,0,0,0,0,0,0,0,0,0}
getReady()
while ind < SIZE
getNumbers()
stop
getReady()
ind = 0
sum = 0
return
getNumbers()
cout<< “Enter a number for position ”, ind
input numbers[ind]
sum = sum + numbers[ind]
ind = ind + 1
return
;
finishUp()
avg = sum/SIZE
ind = 0
while ind < SIZE
output numbers[ind], avg – numbers[index]
ind = ind + 1
return
Modify the program in 2a
number index
number sum
number avg
number actualSize
number SIZE = 10
number number[SIZE] = 0