Import java.util.Scanner;
class hola
{
public static void main(String[]args)
{
Scanner x=new Scanner(System.in);
int a=x.nextInt();
int b;
if(a>20&&a<100)
{
b=a%12;
if(b%2==0){
System.out.print("es par"+b);
}
else{
System.out.print("es impar"+b);
}
}
}
}
Answer:
The correct answer to the following question will be Option D.
Explanation:
- A collection of nested title scopes are defined by the class hierarchy, even though a collection of nested methodologies as well as blocks see in an everything else.
- From the all, the lexical role characterizes the connection between certain scopes of names - if method d would be decided to declare somewhere within procedure c, therefore the namespace within the namespace of c would be nested.
- The more common classes in such a family hierarchy were near the peak of the tree as well as more specific classes are towards the edges.
Other choices have no connection with the given situation. So Option D seems to be the right response.
Answer:
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