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zhenek [66]
3 years ago
13

2 Find the radius and diameter of a circle of area:a) 6.16 cm²b) 13.86 cm²​

Mathematics
1 answer:
Marrrta [24]3 years ago
6 0

Answer:

A.

Area = 6.16cm^2

by using Formula,

A=πr^2

6.16=3.14*r^2

r=1.4cm

now,

D=2*r

=2*1.4

=2.8 CM

B

A=13.86

now,

A=πr^2

13.86=3.14*r*r

4.41=r^2

r=2.1

D=2.1*2

=4.2 cm

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Mrrafil [7]
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Answer:

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Step-by-step explanation:

hope this helps u ...

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3 years ago
At 95% confidence, how large a sample should be taken to obtain a margin of error of 0.03 for the estimation of a population pro
Gnom [1K]

Answer:

A sample of 1068 is needed.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

At 95% confidence, how large a sample should be taken to obtain a margin of error of 0.03 for the estimation of a population proportion?

We need a sample of n.

n is found when M = 0.03.

We have no prior estimate of \pi, so we use the worst case scenario, which is \pi = 0.5

Then

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.03 = 1.96\sqrt{\frac{0.5*0.5}{n}}

0.03\sqrt{n} = 1.96*0.5

\sqrt{n} = \frac{1.96*0.5}{0.03}

(\sqrt{n})^{2} = (\frac{1.96*0.5}{0.03})^{2}

n = 1067.11

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A sample of 1068 is needed.

8 0
3 years ago
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8 0
4 years ago
Read 2 more answers
Which is equivalent
arlik [135]

Answer:

D  8√(10) ^3x

Step-by-step explanation:

We have

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We can rewrite the sqrt as ^1/2

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We know that a^b^c = a^(b*c)

10 ^(1/2 *3/4x)

10 ^(3/8 x)

The numerator is the power

The denominator is the root

8√(10) ^3x

8 0
3 years ago
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