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Zinaida [17]
3 years ago
7

Find the derivative of f(x) = 3/x at x = 1

Mathematics
1 answer:
aniked [119]3 years ago
6 0

Answer:

- 3

Step-by-step explanation:

Differentiate f(x) using the power rule

\frac{d}{dx}(ax^{n} ) = nax^{n-1}

Given f(x) = \frac{3}{x} = 3x^{-1}, then

f'(x) = - 3x^{-2} = - \frac{3}{x^2}

f'(1) = - \frac{3}{1} = - 3

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Simplify the Expression. Clear explanation of monomials appreciated - Thanks!
Nataly [62]
I think the answer is .4m^7n^8

Uhh I don’t know how to give it a clear explanation but all I did was multiply them

-0.8•-0.5= .4

M^2•m^5=m^7

n•n^7=n^8

Hope this helps some.
7 0
3 years ago
6. Write equations of the following scenarios in ANY form
Bumek [7]

Answer:

answer is B

Step-by-step explanation:

7 0
3 years ago
Find the minimum sample size needed to estimate the percentage of Democrats who have a sibling. Use a 0.1 margin of error, use a
Brums [2.3K]

Answer:

The minimum sample size is  n  =135

Step-by-step explanation:

From the question we are told that

   The confidence interval is ( lower \ limit  = \  0.44,\ \ \   upper \ limit  = \ 0.51)

    The margin of error is  E =  0.1

   

Generally the sample  proportion can be mathematically evaluated as

     \r p = \frac{ upper \ limit  + lower \ limit }{2}

    \r p = \frac{ 0.51 + 0.44}{2}

    \r p = 0.475

Given that the confidence level is  98% then the level of significance can be mathematically evaluated as

         \alpha = 100 -  98

        \alpha = 2\%

        \alpha =0.02

Next we obtain the critical value of  \frac{\alpha }{2} from the normal distribution table  

   The value is

        Z_{\frac{\alpha }{2} } =  2.33

Generally the minimum sample size is evaluated as

      n  =[ \frac { Z_{\frac{\alpha }{2} }}{E} ]^2 *  \r p (1- \r p )

     n  =[ \frac { 2.33}{0.1} ]^2 *  0.475(1- 0.475 )

     n  =135

6 0
3 years ago
What is the conjugate of the product (2 - i)(1+2i)?
ivann1987 [24]

Answer:

4-3i is the answer.......

Explanation

<u>Product</u>

(2-i)(1+2i) = 2+4i-i-2i²

= 2+4i-i+2

= 4+3i

conjugate of 4+3i is 4-3i

8 0
3 years ago
A clinical psychologist wants to test whether experiencing childhood trauma affects one's self-efficacy in adulthood. He randoml
Verdich [7]

Answer:

Step-by-step explanation:

We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean

For the null hypothesis,

µ = 152.5

For the alternative hypothesis,

µ ≠ 152.5

This is a two tailed test.

Since no population standard deviation is given, the distribution is a student's t.

Since n = 231

Degrees of freedom, df = n - 1 = 231 - 1 = 230

t = (x - µ)/(s/√n)

Where

x = sample mean = 148.9

µ = population mean = 152.5

s = samples standard deviation = 27.4

t = (148.9 - 152.5)/(27.4/√231) = - 2

We would determine the p value using the t test calculator. It becomes

p = 0.047

Since alpha, 0.05 > thanthere sufficient evidence to conclude that the self-efficacy of adults who have experienced childhood trauma differs from that in the general population of individuals the p value, 0.047, then we would reject the null hypothesis. Therefore, At a 5% level of significance, there is sufficient evidence to conclude that the self-efficacy of adults who have experienced childhood trauma differs from that in the general population of individuals

6 0
3 years ago
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