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irga5000 [103]
3 years ago
9

100/9 write as a mixed number plz

Mathematics
1 answer:
stira [4]3 years ago
7 0

Answer: 11 1/9

Step-by-step explanation:

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there are 10 students in a social studies class. three students will be selected to present their term projects today. in how ma
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4 years ago
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I need help solving this
Gemiola [76]
Since the graphic shows you that both angles across from both of the sides are equal we can tell that both sides are equal. 
Now to solve for the variable all you need to do is make an equation where both of the sides are equal to each other. 
So...8x - 12 = 12x - 18
Now to solve you need to get rid of the constants, or regular numbers. To do this, add 12 to both sides. 
So...8x = 12x - 6
Next, you need to move the variable to one side, do this by subtracting 12x from both sides. 
So... -6x = -6
Finally, divide both sides by -6 to get what the variable equals. 
So...x = 1
Your final answer is both sides equal 1 in.
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3 years ago
which of the following is the value of a when the function f(x)=3|x| is written in the standard form of an absolute value functi
yarga [219]

Answer:I think it’s c

Step-by-step explanation:

7 0
3 years ago
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Which of the following can you use to find 20 percent of 48?
11Alexandr11 [23.1K]

Answer:

The answer would be B

Step-by-step explanation:

It would be B as if we do... 20/100 ⨉ 48, our process would be the same as 0.2(48)

=20% of 48

=20/100 ⨉ 48

=0.2 ⨉ 48

=9.6

Hope this helps andmark this as Brainliest if it really helps! Peace Out!!! ✌

7 0
3 years ago
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Help me with this math question please I'm giving away brainliests ​
alex41 [277]

Answer:

Step-by-step explanation:

Given function is,

f(x)=\frac{2x^2+6x}{-4x^2+8x}

       =\frac{2x(x+3)}{-4x(x-2)}

This function is not defined at "x(x - 2) = 0"

Therefore, for the values of x = 0 and 2, given function is not defined.

Vertical asymptote → x = 2 [Denominator = 0]

For Horizontal asymptote → [\frac{2x^2}{-4x^2} =-\frac{1}{2}]

Therefore, horizontal asymptote → y = -\frac{1}{2}

x-intercept,

For f(x) = 0,

Numerator of the function = 0

2x² + 6x = 0

2x(x + 3) = 0

x = -3

Therefore, x - intercept → (-3, 0)

For y-intercept,

x = 0

f(0) = 0

Therefore, graph has no y-intercept.

For holes on the graph,

Since, function is not defined at x = 0,

f(x) = \frac{(x+3)}{-2(x-2)}

f(0) = \frac{(0+3)}{-2(0-2)}

     = \frac{3}{4}

Therefore, hole on the graph → (0, \frac{3}{4})

8 0
3 years ago
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