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3 years ago

Radium-228 has a half-life of 5.75 years. What is the decay rate for radium-228?

Mathematics

1 answer:

artcher [175]3 years ago

3 0

Decay rate for Radium-228 is 0.01205

Step-by-step explanation:

The half life of radium-228 is 5.75 years. We need to find the decay rate for radium.

The formula used is:

$ln\frac{N_o}{N_t}=-\lambda t$

Where N₀ = amount of radioactive particles at time = 0

N_t = amount of radioactive particles are time (t)

λ = rate of decay constant

t = time

We are given half life so, $\frac{N_o}{N_t}$ =0.5

t= 5.75 years

We need to find λ

Putting values in formula and solving:

$ln\frac{N_o}{N_t}=-\lambda t$

$ln(0.5)=-\lambda *5.75\\-\lambda=\frac{ln(0.5)}{5.75}\\-\lambda=\frac{-0.69}{5.75}\\-\lambda=-0.1205\\\lambda=0.1205$

So, Decay rate for Radium-228 is 0.01205.

Keywords: Decay Rate

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See attachment

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