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4 years ago

14

6x-3y=20 through (4,-3)

1 answer:

tensa zangetsu [6.8K]4 years ago

7 0

Well x = 4 and y = -3 so what we would do is plug in the numbers like this.
6 x 4-3 x -3 = 20
Then lets break down the problem.
6x4=24 and 3x-3=-9
Now plug those numbers into our equation.
24 - (-9)=20
Then figure out the problem.
24 - (-9) = 33
So the x,y is wrong.

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Question:

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Answer:

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Step-by-step explanation:

Given

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$

Required

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$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\frac{2}{\sqrt{3}}}{ \frac{4}{3}}$

Express the fraction as:

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$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= \frac{\sqrt{3}}{2}$

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$sin(60^{\circ}) = \frac{\sqrt{3}}{2}$

Hence:

$\frac{2tan30^{\circ}}{1 + tan^2(30^{\circ})}$ $= sin(60^{\circ})$

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