1 answer:
Answer:
(0, -1)
Step-by-step explanation:
x becomes x - 6, so subtract 6 from the x-coordinate.
y becomes y - 1, so subtract 1 from the y-coordinate.
P(6, 0) -----> P'(0, -1)
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For the limit approaching 3 from the right, you want to follow the line to the right of x = 3. From the graph you're describing it sounds like that's y = -3.
The RHS limit is -3 even though f(3) = 7
Answer:
x^3 -2x^2 -1 + (x-1)
= x^3 -2x^2 + x -2
= (x-2)(x^2+1)
Hope this helps!
Answer:
9/8 I think I could be wrong tho
<span>False. Perimeter is a linear measure. Square units are for area.</span>
Answer:
we should multiply by 6 to get rid of the fractions in problem
