The answer is 3x10^12 also can i get brainliest please??
Step-by-step explanation:
<u>Formula:</u>
r represents the radius.
The radius is 1/2 of the diameter.
Since 1/2 of 16 is 8, 8 is our radius.
<u>Substitute:</u>
<u>Solve:</u>
Answer:
Decreased
Strong negative
Step-by-step explanation:
The correlation Coefficient is used to show the strength and type of relationship which exists between the dependent and independent variable. The correlation Coefficient value ranges from - 1, to 1. With values closer to either - 1 or 1 depicting a strong relationship while those closer to 0 represents weak relationship. And correlation Coefficient of 0 indicates that no relationship exiata at all. Depending in the sign, that is positive or negative, positive sign means positive relationship while a negative sign represents a negative association. Positive association is interpreted as, for every increase in A, Variable B also increase and vice versa. For negative association, When A increases, B decreases and vice versa
I thought of it as answering a regular equation and imagine it's equal signs but when your done solving you with have like ex x<5 and where ever the butt of the arrow is pointing is where the lines goes if there's ano equal sign below it then it is includive
Answer:
The amount of white paint Jen used to paint the walls in her room is:
Step-by-step explanation:
To solve the exercise you only have to pay attention to the statement, in the section that says that 4/5 parts of the total painting is blue, therefore, if 1 is the total painting, you must do a subtraction:
Since the remaining white paint is 1/5 of the total, you have two ways to solve the exercise: multiply the total paint (8.2 pints) by 1/5 or divide the number by 5, as shown below:
- <u>Amount of white paint = 8.2 pints * (1/5) = 1.64 pints.
</u>
- <u>Amount of white paint = 8.2 pints / 5 = 1.64 pints.
</u>
As you can see, the two methods provide a <u>value of 1.64 pints, which corresponds to 1/5 of the total paint and is the amount of white paint used</u>.
