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stiks02 [169]
3 years ago
6

Which expression is equivalent to 9x^2-2y+3x^2-3y

Mathematics
1 answer:
Thepotemich [5.8K]3 years ago
4 0

Answer:The answer is choice B

Step-by-step explanation: (3x-2y)2-(2x-3y)2  

Final result :

 5 • (x + y) • (x - y)

Step by step solution :

Step  1  :

1.1     Evaluate :  (3x-2y)2   =    9x2-12xy+4y2  

1.2     Evaluate :  (2x-3y)2   =    4x2-12xy+9y2  

Step  2  :

Pulling out like terms :

2.1     Pull out like factors :

  5x2 - 5y2  =   5 • (x2 - y2)  

Trying to factor as a Difference of Squares :

2.2      Factoring:  x2 - y2  

Theory : A difference of two perfect squares,  A2 - B2  can be factored into  (A+B) • (A-B)

Proof :  (A+B) • (A-B) =

        A2 - AB + BA - B2 =

        A2 - AB + AB - B2 =

        A2 - B2

Note :  AB = BA is the commutative property of multiplication.

Note :  - AB + AB equals zero and is therefore eliminated from the expression.

Check :  x2  is the square of  x1  

Check :  y2  is the square of  y1  

Factorization is :       (x + y)  •  (x - y)  

Final result :

 5 • (x + y) • (x - y)

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ElenaW [278]

The equation of the central street PQ is  -1.5x - 3.5y = -31.5 option (b) is correct.

<h3>What is a straight line?</h3>

A straight line is a combination of endless points joined on both sides of the point.

We have a straight line:

-7x+3y=-21.5  

Convert it to the general form given below:

\rm y=mx+c

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\rm y = \frac{7}{3}x-\frac{21.5}{3}

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\rm m'=-\frac{1}{m}    ( because AB and PQ are perpendicular to each other)

\rm m' = -\frac{3}{7}

We know the:

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Where (x', y') = (7, 6), we get:

\rm (y-6)=-\frac{3}{7} (x-7)

\rm 7(y-6)=-3 (x-7)\\\\\rm 7y-42= -3x+21\\\\\rm 7y= -3x+21+42\\\\\rm 3x+7y=63

\rm -1.5x-3.5y=-31.5   (multiply by -1/2 on both sides)

Thus, the equation of the central street PQ is  -1.5x - 3.5y = -31.5

Learn more about the straight line.

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