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3 years ago

Jackson bought 5 ounces of raisins for $4. How much could he have buy for 1$?

Mathematics

2 answers:

Leya [2.2K]3 years ago

7 0

Answer:

x= 1 1/4 ounces

Step-by-step explanation:

We can use a proportion to solve this problem. Put the cost over the number of ounces.

$4 $1

---------- = ---------------

5 ounces x ounces

Using cross products

4x =1*5

Divide each side by 4

x =5/4

x= 1 1/4 ounces

Yuliya22 [10]3 years ago

4 0

If you do 5 divide by 4 then you can find what 1$ would be worth so ie.
5 divide by 4 is 1.25 which means that for 1$ you could buy 1.25 ounces

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How much would you need to deposit in an account now in order to have $4000 in the account in 15 years? Assume the account earns

Finger [1]

Answer:

$2500

Step-by-step explanation:

CA=p(1+MR÷1200)

4000=p(1+180×4÷1200) 15 yrs =15×12=180 month

4000=1.6p

p=4000÷1.6

p=2500

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2 years ago

3х - 5 = -11 what is x

Gennadij [26K]

Answer:

-2

Step-by-step explanation:

Add 5 to both sides to get

3x-5+5=-11+5

and simplify to get

3x = -6

x = -2

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3 years ago

Read 2 more answers

Describe the two equations:<br> y=-3x + 2 and y = 2x - 3

tatuchka [14]

Answer:

(-4,2)

Step-by-step explanation:

3 0

2 years ago

Wendy borrowed a 370-page book from the library. She has already read 20 pages. The book is due back to the library in 7 days. W

Leviafan [203]

Answer:

n ≥ 50

Step-by-step explanation:

Total pages = 370

Read pages = 20

Number of days remaining = 7

Reading rate per day = n

7n + 20 ≥ 370

7n ≥ 370 - 20

7n ≥ 350

n ≥ 350/7

n ≥ 50 pages per day for the remaining 7 days

5 0

3 years ago

Let A be a set of numbers.

LUCKY_DIMON [66]

Answer:

a. closed under addition and multiplication

b. not closed under addition but closed under multiplication.

c. not closed under addition and multiplication

d. closed under addition and multiplication

e. not closed under addition but closed under multiplication

Step-by-step explanation:

Let A be a set of all integers divisible by 5.

Let $x,y$ ∈A such that $x=5m\,,\,y=5n$

Find $x+y,xy$

$x+y=5m+5n=5(m+n)$

So, $x+y$ is divisible by 5.

$xy=(5m)(5n)=25mn=5(5mn)$

So,

$xy$ is divisible by 5.

Therefore, A is closed under addition and multiplication.

Let A = { 2n +1 | n ∈ Z}

Let $x,y$ ∈A such that $x=2m+1\,,\,y=2n+1$ where m, n ∈ Z.

Find $x+y,xy$

$x+y=2m+1+2n+1=2m+2n+2=2(m+n+1)$

So,

$x+y$ ∉ A

$xy=(2m+1)(2n+1)=4mn+2m+2n+1=2(2mn+m+n)+1$

So,

$xy$ ∈ A

Therefore, A is not closed under addition but A is closed under multiplication.

$Let A=\{2,5,8,11,14,...\}$

Let $x=2,y=5$ but $x+y=2+5=7$ ∉A

Also,

$xy=2(5)=10$ ∉A

Therefore, A is not closed under addition and multiplication.

Let A = { 17n: n∈Z}

Let $x,y$ ∈ A such that $x=17n,y=17m$

Find x + y and xy

$x+y=17n+17m=17(n+m)$

$xy=(17m)(17n)=289mn=17(17mn)$

So,

$x+y,xy$ ∈ A

Therefore, A is closed under addition and multiplication.

Let A be the set of nonzero real numbers.

Let $x,y$ ∈ A such that $x=-1,y=1$

Find x + y

$x+y=-1+1=0$

So,

$x+y$ ∈ A

Also, if x and y are two nonzero real numbers then xy is also a non-zero real number.

Therefore, A is not closed under addition but A is closed under multiplication.

4 0

3 years ago