Answer:
0.14
Step-by-step explanation:
From the question given above, the following data were obtained:
Grade A = 5
Grade B = 10
Grade C = 15
Grade D = 3
Grade F = 2
Sample space (S) = 35
Probability of getting grade A, P(A) =?
The probability that a student obtained a grade of A can be obtained as follow:
Probability of getting grade A, P(A) =
Event of A (nA) / Sample space, (nS)
P(A) = nA/nS
P(A) = 5/35
P(A) = 0.14
Thus, probability that a student obtained a grade of A is 0.14
Distance = 500 miles
Distance of automobile = 10r
r = 50
Distance = 10 x 50 = 500 miles
5x - 2y + 1z = 8 ⇒ 5x - 2y + 1z = 8
-9x + 2y + 2z = 5 ⇒ -9x + 2y + 2z = 5
-9x - 2y - 5z = 4 -4x + 3z = 13
5x - 2y + 1z = 8
-9x + 2y + 2z = 5 ⇒ -9x + 2y + 2z = 5
-9z - 2y - 5z = 4 ⇒ -9x - 2y - 5z = 4
-18x - 3z = 9
-4x + 3z = 13
-18x - 3z = 9
-22x = 22
-22 -22
x = -1
-18x - 3z = 9
-18(-1) - 3z = 9
18 - 3z = 9
- 18 - 18
-3z = -9
-3 -3
z = 3
5x - 2y + z = 8
5(-1) - 2y + 3 = 8
-5 - 2y + 3 = 8
-2y - 5 + 3 = 8
-2y - 2 = 8
+ 2 + 2
-2y = 10
-2 -2
y = -5
(x, y, z) = (-1, -5, 3)
Answer:
1. 424
2.471
3.512
Step-by-step explanation:
1. 10×12+8×10+8×13+8×15
=120+80+104+120
=424
2. 5×24+9×24+9×15+9×15
=120+216+135
=471
3. 24×16+2×24+2×20+2×20
=384+48+40+40
=512
Let's assume
x represents the number of $25 tickets
y represents the number of $50 tickets
A total of 1,250 tickets
so, we get
So, cost of $25 tickets is 25x
So, cost of $50 tickets is 50y
Total cost of tickets =(cost of $25 tickets)+(cost of $50 tickets)
Total cost of tickets =25x+50y
we are given
worth $50,000, were sold
so, we get equation as
we get system of equations as
..............Answer
