Answer:
The 95% confidence interval for the population variance is (8.80, 32.45).
Step-by-step explanation:
The (1 - <em>α</em>)% confidence interval for the population variance is given as follows:

It is provided that:
<em>n</em> = 20
<em>s</em> = 3.9
Confidence level = 95%
⇒ <em>α</em> = 0.05
Compute the critical values of Chi-square:

*Use a Chi-square table.
Compute the 95% confidence interval for the population variance as follows:


Thus, the 95% confidence interval for the population variance is (8.80, 32.45).
Answer:
The correct answer is option (C)-0.245 = 2.160(0.205)
Step-by-step explanation:
Solution
Given that:
The slope = - 0.245
The size sample = n = 15
The standard error = 0.205
The confidence level = 95
The Significance level= α = (100- 95)% = 0.05
Now,
The freedom of degree = n-2 = 15 -2= 13
Thus,
the critical value = t* = 2.16
By applying Excel = [TINV (0.05, 13)]
The Margin of error is = t* (standard error)
=2.16 *0.205
= 0.4428
Two numbers that add up to -19 and multiply to 48 are -16 and -3:

So, the solutions come from each parentheses: x+4=0, x-4=0, and x^2-3=0.
x+4=0
x = -4
x-4=0
x = 4
x^2-3=0
x^2 = 3
x = +/- √3
So, the solutions are -4, -√3, √3, and 4.
Answer:
B.
Step-by-step explanation:
to turn a decimal into a percentile you have to move the decimal point over two spaces to the right.
Step-by-step explanation:
-5(4a) = (-5a)4
(By commutative property of multiplication)