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Morgarella [4.7K]
3 years ago
10

How much of the 8% solution should we use to make 100g of a 3% solution?

Mathematics
1 answer:
kipiarov [429]3 years ago
3 0

Answer:

37.5 g

Step-by-step explanation:

The final solution will contain 3% × 100 g = 3 g of solute. This amount of solute will be found in w grams of 8% solution, where ...

... 3 = 0.08 × w

... 3/0.08 = w = 37.5 . . . . . grams of 8% solution

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Use the information provided to determine a 95% confidence interval for the population variance. A researcher was interested in
Leno4ka [110]

Answer:

The 95% confidence interval for the population variance is (8.80, 32.45).

Step-by-step explanation:

The (1 - <em>α</em>)% confidence interval for the population variance is given as follows:

\frac{(n-1)\cdot s^{2}}{\chi^{2}_{\alpha/2}}\leq \sigma^{2}\leq \frac{(n-1)\cdot s^{2}}{\chi^{2}_{1-\alpha/2}}

It is provided that:

<em>n</em> = 20

<em>s</em> = 3.9

Confidence level = 95%

⇒ <em>α</em> = 0.05

Compute the critical values of Chi-square:

\chi^{2}_{\alpha/2, (n-1)}=\chi^{2}_{0.05/2, (20-1)}=\chi^{2}_{0.025,19}=32.852\\\\\chi^{2}_{1-\alpha/2, (n-1)}=\chi^{2}_{1-0.05/2, (20-1)}=\chi^{2}_{0.975,19}=8.907

*Use a Chi-square table.

Compute the 95% confidence interval for the population variance as follows:

\frac{(n-1)\cdot s^{2}}{\chi^{2}_{\alpha/2}}\leq \sigma^{2}\leq \frac{(n-1)\cdot s^{2}}{\chi^{2}_{1-\alpha/2}}

\frac{(20-1)\cdot (3.9)^{2}}{32.852}\leq \sigma^{2}\leq \frac{(20-1)\cdot (3.9)^{2}}{8.907}\\\\8.7967\leq \sigma^{2}\leq 32.4453\\\\8.80\leq \sigma^{2}\leq 32.45

Thus, the 95% confidence interval for the population variance is (8.80, 32.45).

4 0
2 years ago
19. James has a desk job and would like to become more fit, so he purchases a
Neko [114]

Answer:

The correct answer is option (C)-0.245 = 2.160(0.205)

Step-by-step explanation:

Solution

Given that:

The slope = - 0.245

The size sample = n = 15

The standard error = 0.205

The confidence level = 95

The Significance level= α = (100- 95)% = 0.05

Now,

The freedom of degree = n-2 = 15 -2= 13

Thus,

the critical value = t* = 2.16

By applying Excel = [TINV (0.05, 13)]

The Margin of error is = t* (standard error)

=2.16 *0.205

= 0.4428

8 0
2 years ago
How to solve X^4-19x^2+48=0
ZanzabumX [31]
Two numbers that add up to -19 and multiply to 48 are -16 and -3:

(x^4-19x^2+48)=0\\(x^2-16)(x^2-3)=0\\(x+4)(x-4)(x^2-3)=0

So, the solutions come from each parentheses:  x+4=0, x-4=0, and x^2-3=0.

x+4=0
x = -4

x-4=0
x = 4

x^2-3=0
x^2 = 3
x = +/- √3

So, the solutions are -4, -√3, √3, and 4.
4 0
3 years ago
What is 0.27 as a percent?<br> A)0.27%<br> B)27%<br> C)2.7%<br> D)270%
zaharov [31]

Answer:

B.

Step-by-step explanation:

to turn a decimal into a percentile you have to move the decimal point over two spaces to the right.

6 0
2 years ago
Read 2 more answers
Please help (Its multiple choice)
artcher [175]

Step-by-step explanation:

-5(4a) = (-5a)4

(By commutative property of multiplication)

4 0
3 years ago
Read 2 more answers
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