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sleet_krkn [62]
3 years ago
6

The outside temperature was 73°f at 1.p.m and decreases at a rate of 1.5°f each hour. What expression can be used to determine t

he temperature h(h is the variable) hours after 1.p.m?
Mathematics
1 answer:
disa [49]3 years ago
4 0
Your expression will be h = -1.5°x + 73°
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Use the product, quotient, and power rules of logarithms to rewrite the expression as a single logarithm. Assume that all variab
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Answer:

log(x^7·y^2)

Step-by-step explanation:

The applicable rules are ...

... log(a^b) = b·log(a)

... log(ab) = log(a) +log(b)

_____

The first term, 7log(x) can be rewritten as log(x^7). Note that an exponentiation operator is needed when this is written as text.

The second term 2log(y) can be rewritten as log(y^2). These two rewrites make use of the first rule above.

Now, you have the sum ...

... log(x^7) +log(y^2)

The second rule tells you this can be rewritten as ...

... log(x^7·y^2) . . . . . seems to match the intent of the 3rd selection

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3 years ago
Find the median of the data set: -66, -48, -52, -42
olga2289 [7]
-66, -52, - 48, -42


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6 0
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Solve the system: <br> 2x+6y=36<br> x+4y=20
Assoli18 [71]

<u>Let's solve this problem step-by-step</u>

<u>Let's set</u>:

   2x + 6y = 36 -- equation 1

   x + 4y = 20 -- equation 2

(equation 2) * 2

   2x + 8y = 40 -- equation 3

(equation 3) - (equation 1)

   2y = 4

   y = 2 -- equation 4

Plug (equation 4)'s value of y into (equation 2)

   x + 4(2) = 20

   x = 20 - 8

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<u>Thus x = 12 and y = 2</u>

<u>Let's check, by substituting these values</u>

  2x + 6y = 36\\2(12)+6(2) = 36\\24+12=36\\36=36\\\\x+4y=20\\12+4(2)=20\\12+8=20\\20=20

<u>Answer: x = 12 and y = 2</u>

Hope that helps!

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eimsori [14]
For this question you need to use the formula: y=p(1+r)^t. P is the principle, or the starting amount, $10,000, r is the rate of growth or decay, and t is the number of years. y=10,000(1.05)^x
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Step-by-step explanation:

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