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kozerog [31]
3 years ago
7

Given an int variable k that has already been declared, write some code that uses a for loop to print a single line consisting o

f 97 asterisks. Use no variables other than k.
Computers and Technology
1 answer:
yawa3891 [41]3 years ago
6 0

Answer:

The program to the given statement can be defined as follows:

Program:

//header file

#include <stdio.h> //defining header file

int main() //defining main method

{

int k; //defining integer variable k

for (k=1;k<=97;k++) //defining for loop

{

printf("*"); //print value asterisks

}

return 0;

}

Output:

*************************************************************************************************

Explanation:

Firstly, the headers file is included in the above C-language, and then the main method is described and all computations are performed with this method, which can be described as follows:

  • Inside the main method, an integer variable k is declared.
  • In the next line, the for loop is declared, which uses the variable k, which starts from 1 and ends when the value of k is less than equal to 97, inside the loop, it will print asterisks.
You might be interested in
what is the molarity of a solution prepared by dissolving 15.0g of sodium hydroxide in enough water to make a total of 225 ml of
Reptile [31]

Answer:

1.6666 g/mol = 1 \frac{2}{3} g/mol

Explanation:

Molar mass of NaOH= 23+16+1 =40g/mol

Mols in 15g = 15/40 mol

If this was dissolved in 225ml of water molarity of the solution is

\frac{15}{40} ÷ 225 x 1000 = 1.6666 g/mol = 1 \frac{2}{3} g/mol

5 0
3 years ago
What's the problem with this code ?
Svet_ta [14]
Hi,

I changed your program using some of the concepts you were trying to use. Hopefully you can see how it works:

#include <string>
#include <iostream>
#include <sstream>
#include <vector>
#include <algorithm>

using namespace std;

int main()
{
   short T;
   cin >> T;
   cin.ignore();

   string str[100];

   for(int i=0; i<T; i++)
   {
      getline(cin, str[i]);
   }

   for (int i = 0; i < T; i++)
   {
      stringstream ss(str[i]);
      string tmp;
      vector<string> v;

      while (ss >> tmp)
      {
          // Let's capitalize it before storing in the vector
          if (!tmp.empty())
          {
              transform(begin(tmp), end(tmp), std::begin(tmp), ::tolower);
              tmp[0] = toupper(tmp[0]);
           }
           v.push_back(tmp);
        }

        if (v.size() == 1)
        {
           cout << v[0] << endl;
        }
        else if (v.size() == 2)
        {
           cout << v[0][0] << ". "  << v[1] << endl;
        }
        else
        {
            cout << v[0][0] << ". " << v[1][0] << ". " << v[2] << endl;
        }
    }

     return 0;
}

4 0
3 years ago
Pick the 3 correct Python functions that parse and output only the date and time part of each log in log.txt as follows.
Mila [183]

Answer:

1, 4, 5

Explanation:

parse2:

. In this case it's passing "r" as an argument, which really does absolutely nothing, because whenever you call open("file.txt") it defaults to reading mode, so all you're doing is explicitly passing the "r". So let's look at the first line. Whenever you call str.split() without any arguments, by default it splits it by empty text, and filters any empty text. So str.split() is not the same as str.split(" ") although it has similar behavior. "     ".split(" ") will output ['', '', '', '', '', ''], while "     ".split() will output []. So in this case the line.split() will split the string '10.1.2.1 - car [01/Mar/2022:13:05:05  +0900] "GET /python HTTP/1.0" 200 2222' into the list<em> ['10.1.2.1', '-', 'car', '[01/Mar/2022:13:05:05', '+0900]', '"GET', '/python', 'HTTP/1.0"', '200', '2222'].</em> As you can see the the data is split into two pieces of text, AND they include the brackets in both strings. So when it gets the 3 index and strips it of the "[]" it will have the incomplete date

parse3:

 In this instance the "r" does nothing as mentioned before the "r" is already defaulted whenever you call open("file.txt") so open("file.txt") is the same as open("file.txt", "r"). So in this case we won't be working left to right, we're going inside the brackets first, kind of like in math you don't don't work left to right in equation 3 + 3(2+3). You work in the brackets first (inside brackets you do left to right). So the first piece of code to run is the line.split("[" or "]"). I actually kind of misspoke here. Technically the "[" or "]" runs first because this doesn't do what you may think it does. The or will only return one value. this is not splitting the line by both "[" and "]". The, or will evaluate which is true from left to right, and if it is true, it returns that. Since strings are evaluated on their length to determine if they're true. the "[" will evaluate to true, because any string that is not empty is true, if a string is empty it's false. So the "[" will evaluate to true this the "[" or "]" will evaluate to "[". So after that the code will run line.split("[") which makes the list: <em>['10.1.2.1 - car ', '01/Mar/2022:13:05:05  +0900] "GET /python HTTP/1.0" 200 2222']</em>. Now the [3:5] will splice the list so that it returns a list with the elements at index 3 (including 3) to 5 (excluding 5). This returns the list: [], because the previous list only has 2 elements. There are no elements at index 3 to 5 (excluding 5). So when you join the list by " ", you'll get an empty string

parse4:

  So I'm actually a bit confused here, I thought the "r+" would open the file in read-writing mode, but maybe this is a different version of python I have no idea, so I'm going to assume it is reading/writing mode, which just means you can read and write to the file. Anyways when you split the line by doing line.split(), as mentioned before it will split by empty spaces and filter any empty spaces. This line will return: <em>['10.1.2.1', '-', 'car', '[01/Mar/2022:13:05:05', '+0900]', '"GET', '/python', 'HTTP/1.0"', '200', '2222']</em>. and then you splice the list from indexes 3 to 5 (excluding 5). This will return the list: <em>['[01/Mar/2022:13:05:05', '+0900]']</em> which has the two pieces of information you need for the date. Now it joins them by a space which will output: '[01/Mar/2022:13:05:05 +0900]'. Now when you strip the "[]" you get the string: '01/Mar/2022:13:05:05 +0900' which is the correct output!

parse 5:

 So in this example it's using re.split. And the re.split is splitting by "[" or "]" which is what re.split can be used for, to split by multiple strings, which may be confused by string.split("[" or "]") which is not the same thing as explained above what the latter does. Also the reason there is a backslash in front of the [ and ] is to escape it, because normally those two characters would be used to define a set, but by using a \ in front of it, you're essentially telling regex to interpret it literally. So in splitting the string by "[" and "]" you'll get the list: <em>['10.1.2.1 - car ', '01/Mar/2022:13:05:05  +0900', ' "GET /python HTTP/1.0" 200 2222']</em> which has 3 elements, since it was split by the [ and the ]. The second element has the date, so all you need to do is index the list using the index 1, which is exactly what the code does

8 0
2 years ago
When formatting numbers with the Comma Number Format tool, the numbers are formatted with _________.
irina [24]

Answer:

2 decimal places

Explanation:

5 0
3 years ago
How can you use the Address Book to address an email message? Use the drop-down menus to complete the sentences. 1. Type an emai
Delvig [45]

Answer:

1. AutoCorrect

2. Address book

Explanation:

stan bts ?

5 0
3 years ago
Read 2 more answers
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