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3 years ago

Compare attributes of a cube and cylinder

1 answer:

3 0

A cube has all square faces which are connected by other square faces. A cylinder has two round faces connected by a "tube". A cube has 8 vertices and a cylinder has zero vertices.

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Please help me <br><br>If 180°<α<270°, cos⁡ α=−8/17, what is sin -α?

rewona [7]

Starting from the fundamental trigonometric equation, we have

$\cos^2(\alpha)+\sin^2(\alpha)=1 \iff \sin(\alpha)=\pm\sqrt{1-\cos^2(\alpha)}$

Since $180$ , we know that the angle lies in the third quadrant, where both sine and cosine are negative. So, in this specific case, we have

$\sin(\alpha)=-\sqrt{1-\cos^2(\alpha)}$

Plugging the numbers, we have

$\sin(\alpha)=-\sqrt{1-\dfrac{64}{289}}=-\sqrt{\dfrac{225}{289}}=-\dfrac{15}{17}$

Now, just recall that

$\sin(-\alpha)=-\sin(\alpha)$

to deduce

$\sin(-\alpha)=-\sin(\alpha)=-\left(-\dfrac{15}{17}\right)=\dfrac{15}{17}$

6 0

3 years ago

Read 2 more answers

Which two complex numbers that could have been added together to make -11+3i

irina [24]

Answer:

Step-by-step explanation:

There are an infinite number of possible solutions.

here's a few

(1 - 4i) + (-12 + 4i)

(-5.5 + 2i) + (-5.5 + i)

(-24 - 27i) + (13 + 30i)

3 0

3 years ago

a six sided number cube has faces with the numbers 1 through 6 marked on them. what is the probability that a number less than 2

iris [78.8K]

Solution:

we are given that

A six sided number cube has faces with the numbers 1 through 6 marked on them.

we have been asked to find the probability that a number less than 2 will occur on one toss of the number cube.

Since a number less than 2 is only one and that is "1" and total number of possible outcome is 6.

and as we know that probability is given using the formula

$P(E)= \frac{n(E)}{n(S)}\\ \\$

Substitute the values we get

$P(E)= \frac{1}{6}$

Hence the required probability is 1/6.

5 0

3 years ago

Read 2 more answers

C=Wtc/1000 for W please I need help it's algebra

DedPeter [7]

C1000÷ct=w

you pretty much ×1000 and then ÷t and c

3 0

3 years ago

Find the Area of the figure below, composed of a rectangle and a semicircle. Round to the nearest tenth place.

kap26 [50]

Answer: 68.1

Step-by-step explanation:

The area of a semi-circle is 1/2 the area of a full circle. The area of a full circle is pi*r^2. Therefore, the area of a semi-circle is:

$Area=\pi r^2/2$

$Area=\pi (3)^2/2=9\pi /2$

The area of a rectangle is the length multiplied by the width:

$Area=l*w$

$Area=6*9=54$

The net area is the sum of the rectangle and the semi-circle:

$Area=(9\pi /2)+(54)=68.1$

8 0

2 years ago