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exis [7]
2 years ago
5

Liza wants to have more than $750 in her

Mathematics
2 answers:
docker41 [41]2 years ago
8 0

Answer:

x is equal to or greater than 38.

Step-by-step explanation:

use the equation 300+12x to find the amount of money in total dependent on x, the number of hours she worked.

Alla [95]2 years ago
8 0

Step-by-step explanation:

750-300= $450 left that needs to be save to meet her goal.

set an equation to equal 450 that includes the next part of the information given which is $12 and hour

450=12x

isolate x by dividing 12 to both sides

x= 37.5 hrs

the inequality could be :

750<_ 300+ 12x

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Alright, since there are 5 numbers, and the mean (or average) is (sum)/(amount of numbers), we have (sum)/5=14. Multiplying both sides by 5, we have the sum being 80. The median of 10 means that in a, b, c, d, e, 10 has to be c and the numbers have to be in ascending order. A and b must be 10 or lower, while d and e must be 10 or higher. Putting some random numbers in, we can have 1, 1, 10, 15, and e. We left e there because the sum needs to be 80, and since 1+1+10+15=27, 80-27=53=e. This, however, would not work if e was less than 10 and we therefore would have needed to make some numbers lower to compensate for this. Our answer is therefore 1, 1, 10, 15, 53
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Potatoes: Suppose the weights of Farmer Carl's potatoes are normally distributed with a mean of 9 ounces and a standard deviatio
katrin2010 [14]

Answer: a)  79.10 %           b) 7%                c)19.85 %

Step-by-step explanation:

a) Z = ( × - μ ) ÷ σ           Where  μ mean of population σ standard               deviation Z is the abscissa to give the area or probability we are looking for associated to the value 10 ounces ( × )

So:  Z = ( 10 - 9 ) ÷ 1.2  ⇒ Z = 1/1.2 ⇒   Z = 0.83  it has to be below this value

From Z tables we get  P [ Z ≤ 0.82 ] = 0.7910  0r  79.10 %

b) Following the same procedure: We look for

P [ Z > ( x - μ ) ÷   σ ]    ⇒   Z  =  ( 12 -10 ) ÷ 1.2  = 2.5

From Z table we get the area under the curve from the left tail up to the point Z < 2.5 ( 2.5 not included) but we were asked for the area out of that previous so 1- 0.9930 = 0.007 is the area we are looking for

So P (b) = 0.007  or 7 %

Finally between the two points above mentioned ( 10 ≤  Z  ≤ 12 ) we use the previous values (taking in consideration the limits, according to the problem statement )

Z ≤ 10     Z ⇒( 10-9  ) ÷ 1.2   Z = 0.7967

Z ≥ 12     Z ⇒ ( 12 - 9 ) ÷ 1.2  Z = 0.9952

The interval is between these two points

0.9952 - 0.7967 = 0.1985   ⇒ or 19.85 %

The attached help in the understanding of the solution

                               

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