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Pie
3 years ago
12

Which graph represents the function f(x)=−3x−2?

Mathematics
1 answer:
LenaWriter [7]3 years ago
4 0

Answer:

Top left

Step-by-step explanation:

We can plug in the y intercept to find which graph has the correct one.

x = 0 is y intercept

Thus

f(0) = -3^0-2 \\f(0) = -1-2\\f(0)=-3

At this point we known the y intercept is -3 so both graph in the left is considerable.

Notice that the base is the negative, thus the graph would goes down. Therefore the top left would be correct.

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Answer:

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Step-by-step explanation:

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3 years ago
For what value of y does 125=(1/25)^y-1
Alex777 [14]

Answer:y=-1/2

Step-by-step explanation:

125=(1/25)^(y-1)

5^3=(5^(-2))^(y-1)

5^3=5^(-2(y-1))

The same base eliminate each other we then have

3=-2(y-1)

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Collect like terms

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3 years ago
Read 2 more answers
A telescope contains both a parabolic mirror and a hyperbolic mirror. They share focus ​, which is 46feet above the vertex of th
uranmaximum [27]

the center is at the origin of a coordinate system and the foci are on the y-axis, then the foci are symmetric about the origin.

The hyperbola focus F1 is 46 feet above the vertex of the parabola and the hyperbola focus F2 is 6 ft above the parabola's vertex. Then the distance F1F2 is 46-6=40 ft.

In terms of hyperbola, F1F2=2c, c=20.

The vertex of the hyperba is 2 ft below focus F1, then in terms of hyperbola c-a=2 and a=c-2=18 ft.

Use formula c^2=a^2+b^2c

2

=a

2

+b

2

to find b:

\begin{gathered} (20)^2=(18)^2+b^2,\\ b^2=400-324=76 \end{gathered}

(20)

2

=(18)

2

+b

2

,

b

2

=400−324=76

.

The branches of hyperbola go in y-direction, so the equation of hyperbola is

\dfrac{y^2}{b^2}- \dfrac{x^2}{a^2}=1

b

2

y

2

−

a

2

x

2

=1 .

Substitute a and b:

\dfrac{y^2}{76}- \dfrac{x^2}{324}=1

76

y

2

−

324

x

2

=1 .

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2 years ago
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Answer:

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