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qwelly [4]
3 years ago
14

HELP ASAP 0.9 x ___=0.27

Mathematics
1 answer:
9966 [12]3 years ago
5 0

Answer:

0.3

Step-by-step explanation:

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Find the exact value of sin (x-y) if sinx=4/9 and siny=1/4
Svetach [21]

Answer:

sin(x - y) = 0.21

Step-by-step explanation:

we have the sin values which we need to get cos values

sin (A-B) = sin A cos B - sin B cos A

sin² A + cos² A = 1

sin x = 4/9

cos² x = 1 - sin² x = 1 - 16/81 = 65/81

cos² x = 65/81

cos x = √65/9

sin y = 1/4

cos² y = 1 - sin² y = 1 - 1/16 = 15/16

cos² y = 15/16

cos y = √15/4

sin(x − y) = sin x cos y - sin y cos x

sin(x - y) = 4/9 √15/4 - 1/4 √65/9

sin(x - y) = (4√15-√65)/36

sin(x - y) = 0.21

socratic Narad T

8 0
2 years ago
Can some one help me with this question its hard :( down below ill give brainliest
Jet001 [13]

Answer: A. Suzy made an error going from Step 1 to Step 2.

Step-by-step explanation: Following the order of operations (PEMDAS), we know that exponents are dealt with before multiplication. Suzy used the distributive property of multiplication going from step 1 to step 2, rather than working with the exponent.

6 0
3 years ago
Simple math question<br> 1)
DedPeter [7]

Answer:

x^10

Step-by-step explanation:

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5 0
3 years ago
Read 2 more answers
Find the area of the part of the paraboloid z = 9 - x^2 - y^2 that lies above the xy-plane.
svetoff [14.1K]

Parameterize this surface (call it S) by

\vec r(u,v)=u\cos v\,\vec\imath+u\sin v\,\vec\jmath+(9-u^2)\,\vec k

with 0\le u\le3 and 0\le v\le2\pi. Take the normal vector to S to be

\vec r_u\times\vec r_v=2u^2\cos v\,\vec\imath+2u^2\sin v\,\vec\jmath+u\,\vec k

Then the area of S is

\displaystyle\iint_S\mathrm dA=\iint_S\|\vec r_u\times\vec r_v\|\,\mathrm du\,\mathrm dv

=\displaystyle\int_0^{2\pi}\int_0^3u\sqrt{1+4u^2}\,\mathrm du\,\mathrm dv

=\displaystyle2\pi\int_0^3u\sqrt{1+4u^2}\,\mathrm du=\boxed{\frac{37\sqrt{37}-1}6\pi}

3 0
4 years ago
Write the fraction as a mixed number
zlopas [31]
LOL that was funny but write which fraction as a mixed number ?
3 0
3 years ago
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